4. (a) Find the first three terms, in ascending powers of $x$, of the binomial expansion of
\[ \frac{1}{\sqrt{4 - x}} \]
giving each coefficient in its simplest form - Edexcel - A-Level Maths Pure - Question 6 - 2019 - Paper 2
Question 6
4. (a) Find the first three terms, in ascending powers of $x$, of the binomial expansion of
\[ \frac{1}{\sqrt{4 - x}} \]
giving each coefficient in its simplest fo... show full transcript
Worked Solution & Example Answer:4. (a) Find the first three terms, in ascending powers of $x$, of the binomial expansion of
\[ \frac{1}{\sqrt{4 - x}} \]
giving each coefficient in its simplest form - Edexcel - A-Level Maths Pure - Question 6 - 2019 - Paper 2
Step 1
Find the first three terms, in ascending powers of $x$, of the binomial expansion of \[ \frac{1}{\sqrt{4 - x}} \]
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To find the first three terms of the binomial expansion, we can rewrite ( \frac{1}{\sqrt{4 - x}} ) as ( (4 - x)^{-\frac{1}{2}} ). Using the binomial expansion formula ( (1 + u)^n ), we set ( u = -\frac{x}{4} ) and ( n = -\frac{1}{2} ).
Second term: (-\frac{1}{2} \left( -\frac{x}{4} \right) = \frac{x}{8} )
Third term: ( \frac{-\frac{1}{2} \left(-\frac{3}{2}\right)}{2} \left(-\frac{x}{4}\right)^2 = \frac{3x^2}{128} )
Thus, the first three terms of the expansion are:
[ 1 + \frac{x}{8} + \frac{3x^2}{128} ]
Step 2
state, giving a reason, which of the three values of \( x \) should not be used
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
x=−14 should not be used because the expansion is only valid for (|u| < 1), leading to the condition (|-\frac{x}{4}| < 1), or equivalently, (-4 < x < 4). Since (x = -14) is outside this range, it would render the expansion invalid.
Step 3
state, giving a reason, which of the three values of \( x \) would lead to the most accurate approximation to \( \sqrt{2} \)
96%
101 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
x=2 would lead to the most accurate approximation because it results in the expansion converging exactly to ( \sqrt{2} ), while the other values would introduce inaccuracies.