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6. (a) Express sin x + 2 cos x in the form R sin(x + a) where R and a are constants, R > 0 and 0 < a < π/2 Give the exact value of R and give the value of a in radians to 3 decimal places - Edexcel - A-Level Maths Pure - Question 7 - 2020 - Paper 1

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6.-(a)-Express-sin-x-+-2-cos-x-in-the-form-R-sin(x-+-a)-where-R-and-a-are-constants,-R->-0-and-0-<-a-<-π/2-Give-the-exact-value-of-R-and-give-the-value-of-a-in-radians-to-3-decimal-places-Edexcel-A-Level Maths Pure-Question 7-2020-Paper 1.png

6. (a) Express sin x + 2 cos x in the form R sin(x + a) where R and a are constants, R > 0 and 0 < a < π/2 Give the exact value of R and give the value of a in radia... show full transcript

Worked Solution & Example Answer:6. (a) Express sin x + 2 cos x in the form R sin(x + a) where R and a are constants, R > 0 and 0 < a < π/2 Give the exact value of R and give the value of a in radians to 3 decimal places - Edexcel - A-Level Maths Pure - Question 7 - 2020 - Paper 1

Step 1

Express sin x + 2 cos x in the form R sin(x + a)

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Answer

To express the equation in the form of R sin(x + a), we can start by finding the values of R and a:

  1. First, calculate R: R=12+22=5R = \sqrt{1^2 + 2^2} = \sqrt{5}

  2. Next, find the angle a using the tangent function: tana=21=2a=tan1(2)1.107 radians\tan a = \frac{2}{1} = 2 \Rightarrow a = \tan^{-1}(2) \approx 1.107 \text{ radians}

Thus, the expression can be rewritten as: Rsin(x+a)=5sin(x+1.107)R \sin(x + a) = \sqrt{5} \sin(x + 1.107)

Step 2

Deduce the maximum temperature of the room during this day

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Answer

Using the expression for temperature: θ=5+sin(π12i3)+2cos(π123)θ = 5 + \sin(\frac{\pi}{12} i - 3) + 2 \cos(\frac{\pi}{12} - 3)

To find the maximum temperature, we need to determine the maximum value of the sine and cosine functions. The maximum value of sin(x)\sin(x) is 1 and for cos(x)\cos(x) is also 1. Therefore:

  1. Maximum contribution from sine: 1
  2. Maximum contribution from cosine: 2

Thus, the maximum temperature can be calculated as: θmax=5+1+2=8°Cθ_{max} = 5 + 1 + 2 = 8°C

Step 3

Find the time of day when the maximum temperature occurs

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Answer

To find the time, we identify when the sine and cosine reach their maximum values:

  1. For maximum sin(π12i3)\sin(\frac{\pi}{12} i - 3), set it to equal 1: π12i3=π2+2kπ\frac{\pi}{12} i - 3 = \frac{\pi}{2} + 2k\pi Simplifying, we find: π12i=3+π2+2kπ\frac{\pi}{12} i = 3 + \frac{\pi}{2} + 2k\pi Solving for i gives multiple angles, but the first relevant is when i=13.2i = 13.2.

  2. So the time is approximately: i=13.213:12extor1:12PMi = 13.2 \Rightarrow 13:12 ext{ or } 1:12 PM

Thus, the maximum temperature occurs at approximately 1:14 PM.

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