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Express $9^{x+1}$ in the form $3^y$, giving $y$ in the form $ax + b$, where $a$ and $b$ are constants. - Edexcel - A-Level Maths Pure - Question 4 - 2016 - Paper 1

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Express-$9^{x+1}$-in-the-form-$3^y$,-giving-$y$-in-the-form-$ax-+-b$,-where-$a$-and-$b$-are-constants.-Edexcel-A-Level Maths Pure-Question 4-2016-Paper 1.png

Express $9^{x+1}$ in the form $3^y$, giving $y$ in the form $ax + b$, where $a$ and $b$ are constants.

Worked Solution & Example Answer:Express $9^{x+1}$ in the form $3^y$, giving $y$ in the form $ax + b$, where $a$ and $b$ are constants. - Edexcel - A-Level Maths Pure - Question 4 - 2016 - Paper 1

Step 1

Express $9^{x+1}$ as $3^y$

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Answer

First, note that 99 can be expressed as a power of 33:

9=32.9 = 3^2.

Thus, we can rewrite 9x+19^{x+1} as:

9x+1=(32)x+1=32(x+1)=32x+2.9^{x+1} = (3^2)^{x+1} = 3^{2(x+1)} = 3^{2x + 2}.

Step 2

Write in the form $3^y$

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Answer

Now, we want to express this in the form 3y3^y:

y=2x+2.y = 2x + 2.

In this case, we have constants a=2a = 2 and b=2b = 2.

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