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The straight line with equation $y = 3x - 7$ does not cross or touch the curve with equation $y = 2px^2 - 6px + 4p$, where $p$ is a constant - Edexcel - A-Level Maths Pure - Question 10 - 2016 - Paper 1

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The-straight-line-with-equation-$y-=-3x---7$-does-not-cross-or-touch-the-curve-with-equation-$y-=-2px^2---6px-+-4p$,-where-$p$-is-a-constant-Edexcel-A-Level Maths Pure-Question 10-2016-Paper 1.png

The straight line with equation $y = 3x - 7$ does not cross or touch the curve with equation $y = 2px^2 - 6px + 4p$, where $p$ is a constant. (a) Show that $4p^2 - ... show full transcript

Worked Solution & Example Answer:The straight line with equation $y = 3x - 7$ does not cross or touch the curve with equation $y = 2px^2 - 6px + 4p$, where $p$ is a constant - Edexcel - A-Level Maths Pure - Question 10 - 2016 - Paper 1

Step 1

(a) Show that $4p^2 - 20p + 9 < 0$

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Answer

To determine whether the straight line intersects the curve, we can set the two equations equal:

3x7=2px26px+4p3x - 7 = 2px^2 - 6px + 4p

Rearranging gives:

2px2(6p+3)x+(4p+7)=02px^2 - (6p + 3)x + (4p + 7) = 0

For the line not to intersect the curve, the discriminant of the quadratic must be less than zero. The discriminant DD for the equation ax2+bx+c=0ax^2 + bx + c = 0 is given by:

D=b24acD = b^2 - 4ac

Here, we have:

  • a=2pa = 2p
  • b=(6p+3)b = -(6p + 3)
  • c=4p+7c = 4p + 7

Calculating the discriminant, we get:

D=[(6p+3)]24(2p)(4p+7)D = [-(6p + 3)]^2 - 4(2p)(4p + 7)

Simplifying,

D=(6p+3)28p(4p+7)D = (6p + 3)^2 - 8p(4p + 7)

Expanding both sides yields:

(36p2+36p+9)(32p2+56p)(36p^2 + 36p + 9) - (32p^2 + 56p)

This simplifies to:

4p220p+94p^2 - 20p + 9

Thus, we need to show that:

4p220p+9<04p^2 - 20p + 9 < 0

Step 2

(b) Hence find the set of possible values of $p$

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Answer

To solve the inequality 4p220p+9<04p^2 - 20p + 9 < 0, we can first find the roots of the equation 4p220p+9=04p^2 - 20p + 9 = 0 using the quadratic formula:

p=b±b24ac2ap = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

Substituting in our values (a=4,b=20,c=9a = 4, b = -20, c = 9):

p=20±(20)24(4)(9)2(4)p = \frac{20 \pm \sqrt{(-20)^2 - 4(4)(9)}}{2(4)}

Calculating the discriminant:

400144=256400 - 144 = 256

Thus, we have:

p=20±168p = \frac{20 \pm 16}{8}

Calculating the two roots:

  • p=368=4.5p = \frac{36}{8} = 4.5
  • p=48=0.5p = \frac{4}{8} = 0.5

The quadratic 4p220p+94p^2 - 20p + 9 opens upwards (as a>0a > 0), therefore it is negative between the two roots. Thus, the set of possible values for pp is:

0.5<p<4.50.5 < p < 4.5

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