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A sequence $u_1, u_2, u_3, ...$ satisfies t_{n+1} = 2u_n - 1, ext{ for } n > 1 Given that $u_2 = 9$, a) find the value of $u_1$, and the value of $u_4$, b) evaluate $\\sum_{r=1}^4 u_r$. - Edexcel - A-Level Maths Pure - Question 6 - 2013 - Paper 3

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A-sequence-$u_1,-u_2,-u_3,-...$-satisfies--t_{n+1}-=-2u_n---1,--ext{-for-}-n->-1--Given-that-$u_2-=-9$,--a)-find-the-value-of-$u_1$,-and-the-value-of-$u_4$,--b)-evaluate-$\\sum_{r=1}^4-u_r$.-Edexcel-A-Level Maths Pure-Question 6-2013-Paper 3.png

A sequence $u_1, u_2, u_3, ...$ satisfies t_{n+1} = 2u_n - 1, ext{ for } n > 1 Given that $u_2 = 9$, a) find the value of $u_1$, and the value of $u_4$, b) eval... show full transcript

Worked Solution & Example Answer:A sequence $u_1, u_2, u_3, ...$ satisfies t_{n+1} = 2u_n - 1, ext{ for } n > 1 Given that $u_2 = 9$, a) find the value of $u_1$, and the value of $u_4$, b) evaluate $\\sum_{r=1}^4 u_r$. - Edexcel - A-Level Maths Pure - Question 6 - 2013 - Paper 3

Step 1

find the value of $u_1$, and the value of $u_4$

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Answer

To find u1u_1, we can use the given equation:

un+1=2un1u_{n+1} = 2u_n - 1

Starting with n=2n=2:

u3=2u21=2(9)1=17u_3 = 2u_2 - 1 = 2(9) - 1 = 17

Now, applying it again to find u4u_4:

u4=2u31=2(17)1=33u_4 = 2u_3 - 1 = 2(17) - 1 = 33

Thus, the values are:

  • u1=17u_1 = 17
  • u4=33u_4 = 33

Step 2

evaluate $\sum_{r=1}^4 u_r$

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104 rated

Answer

Now, we evaluate the sum:

r=14ur=u1+u2+u3+u4\sum_{r=1}^4 u_r = u_1 + u_2 + u_3 + u_4

We already have:

  • u1=17u_1 = 17
  • u2=9u_2 = 9
  • u3=17u_3 = 17
  • u4=33u_4 = 33

So,

r=14ur=17+9+17+33=76\sum_{r=1}^4 u_r = 17 + 9 + 17 + 33 = 76

Therefore, the evaluation gives us 7676.

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