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1. (a) By writing sin 30° as sin (2θ + θ), show that sin 30° = 3sin θ - 4sin³ θ - Edexcel - A-Level Maths Pure - Question 3 - 2007 - Paper 6

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1.-(a)-By-writing-sin-30°-as-sin-(2θ-+-θ),-show-that-----sin-30°-=-3sin-θ---4sin³-θ-Edexcel-A-Level Maths Pure-Question 3-2007-Paper 6.png

1. (a) By writing sin 30° as sin (2θ + θ), show that sin 30° = 3sin θ - 4sin³ θ. (b) Given that sin θ = \frac{\sqrt{3}}{4}, find the exact value of sin 30°.

Worked Solution & Example Answer:1. (a) By writing sin 30° as sin (2θ + θ), show that sin 30° = 3sin θ - 4sin³ θ - Edexcel - A-Level Maths Pure - Question 3 - 2007 - Paper 6

Step 1

(a) By writing sin 30° as sin (2θ + θ), show that

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Answer

To show that ( \sin 30° = 3\sin \theta - 4\sin^3 \theta ), we can use the angle addition formula for sine:

[ \sin(2\theta + \theta) = \sin 2\theta \cos \theta + \cos 2\theta \sin \theta ]

First, we know from trigonometric identities:

  • ( \sin 2\theta = 2\sin \theta \cos \theta )
  • ( \cos 2\theta = 1 - 2\sin^2 \theta )

Substituting these into the equation gives us:

[ \sin(2\theta + \theta) = (2\sin \theta \cos \theta) \cos \theta + (1 - 2\sin^2 \theta) \sin \theta ]

This leads to:

[ = 2\sin \theta \cos^2 \theta + \sin \theta - 2\sin^3 \theta ]

Using ( \cos^2 \theta = 1 - \sin^2 \theta ), we can substitute again:

[ = 2\sin \theta (1 - \sin^2 \theta) + \sin \theta - 2\sin^3 \theta ]

Expanding yields:

[ = 2\sin \theta - 2\sin^3 \theta + \sin \theta - 2\sin^3 \theta = 3\sin \theta - 4\sin^3 \theta ]

Thus, we have shown that: [ \sin 30° = 3\sin \theta - 4\sin^3 \theta ]

Step 2

(b) Given that sin θ = \frac{\sqrt{3}}{4}, find the exact value of sin 30°.

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Answer

Given ( \sin \theta = \frac{\sqrt{3}}{4} ), we can substitute this into the equation we derived in part (a):

[ \sin 30° = 3\left(\frac{\sqrt{3}}{4}\right) - 4\left(\frac{\sqrt{3}}{4}\right)^3 ]

Calculating the first term:

[ = \frac{3\sqrt{3}}{4} ]

For the second term:

[

  • 4\cdot\frac{\sqrt{3}}{4}\cdot\frac{3\sqrt{3}}{16} = -\frac{3\sqrt{3}}{4} ]

Thus:

[ \sin 30° = \frac{3\sqrt{3}}{4} - \frac{3\sqrt{3}}{16} ]

Finding a common denominator:

[ = \frac{12\sqrt{3}}{16} - \frac{3\sqrt{3}}{16} = \frac{9\sqrt{3}}{16} ]

Therefore, the exact value of ( \sin 30° ) is ( \frac{9\sqrt{3}}{16} ).

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