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Given that $f(x) = \frac{1}{x}, \; x \neq 0,$ (a) sketch the graph of $y = f(x) + 3$ and state the equations of the asymptotes - Edexcel - A-Level Maths Pure - Question 5 - 2007 - Paper 2

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Given-that---$f(x)-=-\frac{1}{x},-\;-x-\neq-0,$----(a)-sketch-the-graph-of-$y-=-f(x)-+-3$-and-state-the-equations-of-the-asymptotes-Edexcel-A-Level Maths Pure-Question 5-2007-Paper 2.png

Given that $f(x) = \frac{1}{x}, \; x \neq 0,$ (a) sketch the graph of $y = f(x) + 3$ and state the equations of the asymptotes. (b) Find the coordinates of t... show full transcript

Worked Solution & Example Answer:Given that $f(x) = \frac{1}{x}, \; x \neq 0,$ (a) sketch the graph of $y = f(x) + 3$ and state the equations of the asymptotes - Edexcel - A-Level Maths Pure - Question 5 - 2007 - Paper 2

Step 1

(a) sketch the graph of $y = f(x) + 3$ and state the equations of the asymptotes.

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Answer

The graph of y=f(x)+3y = f(x) + 3 is a transformation of the basic hyperbola f(x)=1xf(x) = \frac{1}{x}, shifted upwards by 3 units.

Asymptotes:

  1. Vertical Asymptote: The vertical asymptote remains at the line x=0x = 0.
  2. Horizontal Asymptote: The horizontal asymptote shifts to the line y=3y = 3.

This results in the graph having branches in the first and fourth quadrants, approaching both asymptotes but never crossing them.

Step 2

(b) Find the coordinates of the point where $y = f(x) + 3$ crosses a coordinate axis.

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Answer

To find where the graph crosses the y-axis, we set x=0x = 0. However, since f(x)f(x) is undefined at x=0x = 0, we cannot find a crossing on the y-axis.

To find where it crosses the x-axis:
Set y=0y = 0:
0=1x+30 = \frac{1}{x} + 3
This simplifies to:
1x=3\frac{1}{x} = -3
x=13x = -\frac{1}{3}
Thus, the coordinates where the graph crosses the x-axis are (13,0)(-\frac{1}{3}, 0).

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