Given that
$f(x) = \frac{1}{x}, \; x \neq 0,$
(a) sketch the graph of $y = f(x) + 3$ and state the equations of the asymptotes - Edexcel - A-Level Maths Pure - Question 5 - 2007 - Paper 2
Question 5
Given that
$f(x) = \frac{1}{x}, \; x \neq 0,$
(a) sketch the graph of $y = f(x) + 3$ and state the equations of the asymptotes.
(b) Find the coordinates of t... show full transcript
Worked Solution & Example Answer:Given that
$f(x) = \frac{1}{x}, \; x \neq 0,$
(a) sketch the graph of $y = f(x) + 3$ and state the equations of the asymptotes - Edexcel - A-Level Maths Pure - Question 5 - 2007 - Paper 2
Step 1
(a) sketch the graph of $y = f(x) + 3$ and state the equations of the asymptotes.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
The graph of y=f(x)+3 is a transformation of the basic hyperbola f(x)=x1, shifted upwards by 3 units.
Asymptotes:
Vertical Asymptote: The vertical asymptote remains at the line x=0.
Horizontal Asymptote: The horizontal asymptote shifts to the line y=3.
This results in the graph having branches in the first and fourth quadrants, approaching both asymptotes but never crossing them.
Step 2
(b) Find the coordinates of the point where $y = f(x) + 3$ crosses a coordinate axis.
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
To find where the graph crosses the y-axis, we set x=0. However, since f(x) is undefined at x=0, we cannot find a crossing on the y-axis.
To find where it crosses the x-axis:
Set y=0: 0=x1+3
This simplifies to: x1=−3 x=−31
Thus, the coordinates where the graph crosses the x-axis are (−31,0).