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6. (a) Find, to 3 significant figures, the value of x for which 8^x = 0.8 - Edexcel - A-Level Maths Pure - Question 8 - 2007 - Paper 2

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6. (a) Find, to 3 significant figures, the value of x for which 8^x = 0.8. (b) Solve the equation 2 log_3 x - log_3 7 x = 1.

Worked Solution & Example Answer:6. (a) Find, to 3 significant figures, the value of x for which 8^x = 0.8 - Edexcel - A-Level Maths Pure - Question 8 - 2007 - Paper 2

Step 1

(a) Find, to 3 significant figures, the value of x for which 8^x = 0.8.

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Answer

To find the value of x, we start by expressing the equation in logarithmic form:

8x=0.88^x = 0.8

Taking the logarithm (base 10) of both sides gives:

extlog(8x)=extlog(0.8) ext{log}(8^x) = ext{log}(0.8)

Using the power rule of logarithms, we can rewrite it as:

ximesextlog(8)=extlog(0.8)x imes ext{log}(8) = ext{log}(0.8)

Solving for x:

x=extlog(0.8)extlog(8)x = \frac{ ext{log}(0.8) }{ ext{log}(8) }

Calculating the values:

xapprox0.096910.90309approx0.107x \\approx \frac{-0.09691}{0.90309} \\approx -0.107

Thus, the value of x to 3 significant figures is 0.107-0.107.

Step 2

(b) Solve the equation 2 log_3 x - log_3 7 x = 1.

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Answer

To solve the equation, let's rewrite it:

2extlog3xextlog3(7x)=12 ext{log}_3 x - ext{log}_3 (7x) = 1

Using logarithmic properties, we can combine the logs:

2extlog3xextlog37extlog3x=12 ext{log}_3 x - ext{log}_3 7 - ext{log}_3 x = 1

This simplifies to:

This means:

By taking the antilogarithm, we have:

x=21x = 21

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