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Question 6
The curve C has equation y = \frac{x}{9+x^2}. Use calculus to find the coordinates of the turning points of C. Given that y = (1 + e^{x})^{\frac{3}{2}}, find the ... show full transcript
Step 1
Answer
To find the turning points, we first need to compute the first derivative of the function given by
Using the quotient rule, we find:
Setting the derivative equal to zero to find the critical points:
Next, we find the corresponding y-values:
When (x = 3:\n y = \frac{3}{9 + 3^2} = \frac{3}{18} = \frac{1}{6}.$$
When (x = -3:\n y = \frac{-3}{9 + (-3)^2} = \frac{-3}{18} = -\frac{1}{6}.\n Thus, the turning points of the curve are at ((3, \frac{1}{6})) and ((-3, -\frac{1}{6})).
Step 2
Answer
Given the function we will compute the derivative:
Using the chain rule:
Now, we substitute (x = \frac{1}{2} \ln 3:\n e^{x} = e^{\frac{1}{2} \ln 3} = \sqrt{3}.$$
Substituting this in:
Now simplifying,
This gives us the final answer.
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