Photo AI
Question 8
Figure 2 shows a sketch of part of the curve with equation $y = f(x)$ where $f(x) = 8 ext{sin} igg( rac{1}{2}x igg) - 3x + 9$ $x > 0$ and $x$ is measured in ... show full transcript
Step 1
Answer
To find the coordinate of point , we first need to determine the derivative of the function, which gives us the slope of the curve at any point:
f'(x) = 4 ext{cos} igg( rac{1}{2} x igg) - 3
To find the local maximum point, we set the derivative equal to zero:
4 ext{cos} igg( rac{1}{2} x igg) - 3 = 0
This leads to:
ext{cos} igg( rac{1}{2} x igg) = rac{3}{4}
Now we take the inverse cosine:
rac{1}{2} x = ext{cos}^{-1} igg( rac{3}{4} igg)
Hence:
x = 2 ext{cos}^{-1} igg( rac{3}{4} igg)
Calculating this value yields:
Therefore, when rounded to three significant figures:
Step 2
Answer
To explain why must lie in the interval , we evaluate the function values provided:
Since is positive and is negative, by the Intermediate Value Theorem, there must be at least one root in the interval because the function changes sign. This confirms that , the point where the curve crosses the x-axis, must lie within this interval.
Step 3
Answer
For the Newton-Raphson method, we will use the formula:
x_{n+1} = x_n - rac{f(x_n)}{f'(x_n)}
Given our first approximation , we calculate:
Evaluate :
Evaluate : f'(5) = 4 ext{cos} igg( rac{1}{2} imes 5 igg) - 3 = 4 ext{cos}(2.5) - 3 Using a calculator, we find:
Now, substituting into the Newton-Raphson formula:
x_1 = 5 - rac{-1.212}{-6.204}
Rounding this to three significant figures, we have:
Report Improved Results
Recommend to friends
Students Supported
Questions answered