13. (a) Express 10cosθ - 3sinθ in the form Rcos(θ + α), where R > 0 and 0 < α < 90º
Give the exact value of R and give the value of α, in degrees, to 2 decimal places - Edexcel - A-Level Maths Pure - Question 15 - 2017 - Paper 2
Question 15
13. (a) Express 10cosθ - 3sinθ in the form Rcos(θ + α), where R > 0 and 0 < α < 90º
Give the exact value of R and give the value of α, in degrees, to 2 decimal place... show full transcript
Worked Solution & Example Answer:13. (a) Express 10cosθ - 3sinθ in the form Rcos(θ + α), where R > 0 and 0 < α < 90º
Give the exact value of R and give the value of α, in degrees, to 2 decimal places - Edexcel - A-Level Maths Pure - Question 15 - 2017 - Paper 2
Step 1
Express 10cosθ - 3sinθ in the form Rcos(θ + α)
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Answer
To express the given expression in the desired form, we start by identifying the constants involved:
Set up the equation:
R=extsqrt(102+32)=extsqrt(100+9)=extsqrt(109)
To find α, we use the tangent ratio:
an(α)=103
To find α in degrees, calculate:
α=an−1(103)≈16.70º
Thus, the values are:
R = √109
α = 16.70º
Step 2
find a complete equation for the model
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Answer
Given the initial height of 1 metre:
Using the earlier formula:
H=a−10cos(80º)+3sin(80º)
substituting for a:
Since the height is 1 metre at t = 0:
So, we have 1 = a - 10cos(80º) + 3sin(80º)
From here:
Solve to find a = 1 + 10cos(80º) - 3sin(80º).
Thus, complete equation is:
H=(1+10cos(80º)−3sin(80º))−10cos(80º)+3sin(80º)
Step 3
hence find the maximum height of the passenger above the ground
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Answer
The maximum height typically occurs at the peak points of the trigonometric components of the equation.
To find the maximum value of H, we compute:
Evaluate H when sin(80º) is maximized (at 1) and when cos(80º) is minimized (at -1):
Hmax=a+10+3
Substitute the value of a calculated previously:
For maximum height, calculate:
Hmax=(1+10cos(80º)−3sin(80º))+10+3
Substitute numerical values to find H_max.
Step 4
Find the time taken, to the nearest second, for the passenger to reach the maximum height on the second cycle
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Answer
Using the periodic properties of H:
Set while maximizing:
80t+(16.70º)=540
Rearranging leads to:
t=80540−16.70
Compute value to find:
t≈6.54
Thus, time rounded is approximately 6 minutes and 32 seconds.
Step 5
How would you adapt the equation of the model to reflect this increase in speed?
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Answer
To adapt for speed increment:
Increase the coefficient '80' in the original equations in accordance with speed:
For example, use:
H=a−10cos(90º)+3sin(90º)
2. The increase leads to a faster cycle time, thus affecting parameters accordingly.