Given that $y = x^4 + x^3 + 3$, find \( \frac{dy}{dx} \). - Edexcel - A-Level Maths Pure - Question 4 - 2010 - Paper 2
Question 4
Given that $y = x^4 + x^3 + 3$, find \( \frac{dy}{dx} \).
Worked Solution & Example Answer:Given that $y = x^4 + x^3 + 3$, find \( \frac{dy}{dx} \). - Edexcel - A-Level Maths Pure - Question 4 - 2010 - Paper 2
Step 1
Step 1: Find \( \frac{dy}{dx} \)
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Answer
To find ( \frac{dy}{dx} ), we need to differentiate the function (y = x^4 + x^3 + 3). Using the power rule of differentiation, we differentiate each term:
The derivative of (x^4) is (4x^3).
The derivative of (x^3) is (3x^2).
The derivative of a constant (3) is 0.
Thus, we have:
dxdy=4x3+3x2+0=4x3+3x2.
Step 2
Step 2: Evaluate at critical points
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Answer
Next, if we set ( \frac{dy}{dx} = 0 ) to find the critical points, we get:
4x3+3x2=0.
Factoring out the common term:
x2(4x+3)=0.
This gives us (x = 0) or (4x + 3 = 0), which leads to (x = -\frac{3}{4}). These points can be further investigated for maxima, minima, or points of inflection.