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Figure 3 shows the plan of a stage in the shape of a rectangle joined to a semircle - Edexcel - A-Level Maths Pure - Question 3 - 2005 - Paper 2

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Figure 3 shows the plan of a stage in the shape of a rectangle joined to a semircle. The length of the rectangular part is 2x metres and the width is y metres. The d... show full transcript

Worked Solution & Example Answer:Figure 3 shows the plan of a stage in the shape of a rectangle joined to a semircle - Edexcel - A-Level Maths Pure - Question 3 - 2005 - Paper 2

Step 1

Show that the area, A m², of the stage is given by

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Answer

To find the area of the stage, we first express y in terms of x using the perimeter equation:

The perimeter of the stage is given by:

2x+2y+extπx=802x + 2y + ext{π}x = 80

Rearranging the perimeter equation for y gives us:

y=802xextπx2=40xextπ2xy = \frac{80 - 2x - ext{π}x}{2} = 40 - x - \frac{ ext{π}}{2}x

Now, substituting y back into the area formula:

The area A is the sum of the area of the rectangle and the semicircle:

A=2xy+12πx2A = 2xy + \frac{1}{2} \text{π}x²

Substituting for y yields:

A=2x(40xextπ2x)+12πx2A = 2x(40 - x - \frac{ ext{π}}{2}x) + \frac{1}{2} \text{π}x²

This simplifies to:

A=80x2x2πx2A = 80x - 2x² - \text{π}x²

Thus, we arrive at:

A=80x(2+extπ2)x2A = 80x - (2 + \frac{ ext{π} }{ 2 })x²

Step 2

Use calculus to find the value of x at which A has a stationary value.

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Answer

To find the stationary points, we will differentiate the area function A with respect to x and set the derivative to zero:

dAdx=802(2+extπ2)x\frac{dA}{dx} = 80 - 2(2 + \frac{ ext{π} }{ 2 })x

Setting the derivative equal to zero:

802(2+extπ2)x=080 - 2(2 + \frac{ ext{π} }{ 2 })x = 0

Solving for x gives:

x=802(2+extπ2)x = \frac{80}{2(2 + \frac{ ext{π} }{ 2 })}

This value indicates where the area A has a stationary value.

Step 3

Prove that the value of x you found in part (b) gives the maximum value of A.

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Answer

To determine if the stationary point is a maximum, we analyze the second derivative:

Calculating the second derivative:

d2Adx2=2(2+extπ2)\frac{d^2A}{dx^2} = -2(2 + \frac{ ext{π} }{ 2 })

Since this is negative, it indicates that the area function A is concave down at this stationary point, confirming that it is indeed a maximum.

Step 4

Calculate, to the nearest m², the maximum area of the stage.

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Answer

Substituting the value of x back into the area function:

A=80(802(2+extπ2))(2+extπ2)(802(2+extπ2))2A = 80 \left( \frac{80}{2(2 + \frac{ ext{π} }{ 2 })} \right) - (2 + \frac{ ext{π} }{ 2 }) \left( \frac{80}{2(2 + \frac{ ext{π} }{ 2 })} \right)²

After computing this expression, the maximum area A evaluates to approximately 448 m². Thus, the maximum area of the stage, rounded to the nearest m², is:

448 m².

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