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13. (a) Express 10cosθ − 3sinθ in the form Rcos(θ + α), where R > 0 and 0 < α < 90° - Edexcel - A-Level Maths Pure - Question 14 - 2017 - Paper 2

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13.-(a)-Express-10cosθ-−-3sinθ-in-the-form-Rcos(θ-+-α),-where-R->-0-and-0-<-α-<-90°-Edexcel-A-Level Maths Pure-Question 14-2017-Paper 2.png

13. (a) Express 10cosθ − 3sinθ in the form Rcos(θ + α), where R > 0 and 0 < α < 90°. Give the exact value of R and give the value of α, in degrees, to 2 decimal pl... show full transcript

Worked Solution & Example Answer:13. (a) Express 10cosθ − 3sinθ in the form Rcos(θ + α), where R > 0 and 0 < α < 90° - Edexcel - A-Level Maths Pure - Question 14 - 2017 - Paper 2

Step 1

Express 10cosθ − 3sinθ in the form Rcos(θ + α)

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Answer

To express the equation in the given form, we first calculate the value of R using the formula:

R=sqrt(102+(3)2)=sqrt109R = \\sqrt{(10^2 + (-3)^2)} = \\sqrt{109}

Next, we find α using:

tan(α)=310\tan(\alpha) = \frac{-3}{10}

Thus, calculating α gives:

α=tan1(310)16.70°\alpha = \tan^{-1}\left(\frac{-3}{10}\right) ≈ 16.70°.

Step 2

Find a complete equation for the model

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Answer

It is given that the initial height above the ground is 1 metre. Therefore, substituting the value of a:

H=110cos(80t)°+3sin(80t)°H = 1 - 10\cos(80t)° + 3\sin(80t)°.

Step 3

Hence find the maximum height of the passenger above the ground

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Answer

The maximum height can be found when the cosine and sine functions reach their respective maxima. This occurs at:

Hmax=110(1)+3(1)=110+3=6+3=3H_{max} = 1 - 10(1) + 3(1) = 1 - 10 + 3 = -6 + 3 = -3, Thus the maximum height is: Hmax=1+R=1+109=21.44 mH_{max} = 1 + R = 1 + \sqrt{109} = 21.44\text{ m}.

Step 4

Find the time for the passenger to reach the maximum height on the second cycle

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Answer

From the equation set:

80t+16.70=54080t + 16.70 = 540

Rearranging yields:

t=54016.7080=6.54 minutest = \frac{540 - 16.70}{80} = 6.54\text{ minutes}. Converting this into seconds, we get:

t=6 minutes 32 secondst = 6\text{ minutes } 32\text{ seconds}.

Step 5

How would you adapt the equation to reflect the increase in speed?

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Answer

To increase the speed of the Ferris wheel, the value inside the cosine and sine functions (currently at 80) needs to be increased:

H=a10cos(kt)+3sin(kt)H = a - 10\cos(kt) + 3\sin(kt), where k is the new angular speed greater than 80.

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