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Question 7
Water is being heated in a kettle. At time t seconds, the temperature of the water is θ °C. The rate of increase of the temperature of the water at any time t is mo... show full transcript
Step 1
Answer
We start with the given differential equation:
We can rearrange this to separate variables:
Integrate both sides:
This results in:
By exponentiating both sides, we obtain:
Letting , we rearrange it to:
Using the initial condition where (\theta = 20) when (t = 0):
Thus, we can rewrite our equation as:
This shows the required result.
Step 2
Answer
When the kettle switches off, we set (\theta = 100):
Rearranging gives:
Now, dividing both sides by 100:
Taking the natural logarithm:
Thus,
Calculating this we get:
Rounding to the nearest second:
Thus, the kettle switches off at approximately 161 seconds.
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