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Find the first 3 terms, in ascending powers of $x$, of the binomial expansion of \( \left( 2 - \frac{x}{4} \right)^{10} \) giving each term in its simplest form. - Edexcel - A-Level Maths Pure - Question 3 - 2015 - Paper 2

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Find-the-first-3-terms,-in-ascending-powers-of-$x$,-of-the-binomial-expansion-of--\(-\left(-2---\frac{x}{4}-\right)^{10}-\)-giving-each-term-in-its-simplest-form.-Edexcel-A-Level Maths Pure-Question 3-2015-Paper 2.png

Find the first 3 terms, in ascending powers of $x$, of the binomial expansion of \( \left( 2 - \frac{x}{4} \right)^{10} \) giving each term in its simplest form.

Worked Solution & Example Answer:Find the first 3 terms, in ascending powers of $x$, of the binomial expansion of \( \left( 2 - \frac{x}{4} \right)^{10} \) giving each term in its simplest form. - Edexcel - A-Level Maths Pure - Question 3 - 2015 - Paper 2

Step 1

Find the first term

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Answer

The first term of the binomial expansion is given by the formula ( a^{n} ) where ( a = 2 ) and ( n = 10 ). Therefore, the first term is:

210=1024.2^{10} = 1024.

Step 2

Find the second term

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Answer

The second term can be calculated using the formula ( \binom{n}{k} a^{n-k} b^{k} ), where ( n = 10 ), ( k = 1 ), ( a = 2 ), and ( b = -\frac{x}{4} ). This leads to:

(101)29(x4)=10512(x4)=1280x.\binom{10}{1} \cdot 2^{9} \cdot \left(-\frac{x}{4}\right) = 10 \cdot 512 \cdot \left(-\frac{x}{4}\right) = -1280x.

Step 3

Find the third term

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Answer

For the third term, set ( k = 2 ):

(102)28(x4)2=45256x216=720x2.\binom{10}{2} \cdot 2^{8} \cdot \left(-\frac{x}{4}\right)^2 = 45 \cdot 256 \cdot \frac{x^{2}}{16} = 720x^{2}.

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