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Given that $$\frac{2x^{-2}-x^{-3}}{\sqrt{x}}$$ can be written in the form $2x^p - x^q$, (a) write down the value of $p$ and the value of $q$ - Edexcel - A-Level Maths Pure - Question 8 - 2009 - Paper 1

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Given-that---$$\frac{2x^{-2}-x^{-3}}{\sqrt{x}}$$---can-be-written-in-the-form-$2x^p---x^q$,----(a)-write-down-the-value-of-$p$-and-the-value-of-$q$-Edexcel-A-Level Maths Pure-Question 8-2009-Paper 1.png

Given that $$\frac{2x^{-2}-x^{-3}}{\sqrt{x}}$$ can be written in the form $2x^p - x^q$, (a) write down the value of $p$ and the value of $q$. Given that $y... show full transcript

Worked Solution & Example Answer:Given that $$\frac{2x^{-2}-x^{-3}}{\sqrt{x}}$$ can be written in the form $2x^p - x^q$, (a) write down the value of $p$ and the value of $q$ - Edexcel - A-Level Maths Pure - Question 8 - 2009 - Paper 1

Step 1

write down the value of p and the value of q.

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Answer

To express the given function in the form 2xpxq2x^p - x^q, we first simplify the original expression:

2x2x3x=2x2x3x1/2\frac{2x^{-2}-x^{-3}}{\sqrt{x}} = \frac{2x^{-2}-x^{-3}}{x^{1/2}}

Combining the exponents:

=2x21/2x31/2=2x2.5x3.5= 2x^{-2-1/2} - x^{-3-1/2} = 2x^{-2.5} - x^{-3.5}

Thus, we can identify:

  • p=2.5p = -2.5
  • q=3.5q = -3.5.

Step 2

find \(\frac{dy}{dx}\), simplifying the coefficient of each term.

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Answer

Starting from the equation:

y=5x43+2x2x3xy = 5x^4 - 3 + \frac{2x^{-2}-x^{-3}}{\sqrt{x}}

We differentiate term by term:

  1. For 5x45x^4, the derivative is dydx=20x3\frac{dy}{dx} = 20x^3.
  2. The derivative of 3-3 is 00.
  3. For the term 2x2x3x\frac{2x^{-2}-x^{-3}}{\sqrt{x}}, rewrite it as:

2x2x1/2x3x1/2=2x2.5x3.52x^{-2} \cdot x^{-1/2} - x^{-3} \cdot x^{-1/2} = 2x^{-2.5} - x^{-3.5}

Then differentiate:

ddx(2x2.5)=5x3.5andddx(x3.5)=3.5x4.5\frac{d}{dx}(2x^{-2.5}) = -5x^{-3.5} \quad \text{and} \quad \frac{d}{dx}(-x^{-3.5}) = 3.5x^{-4.5}

Now combining all derivatives gives:

dydx=20x35x3.5+3.5x4.5\frac{dy}{dx} = 20x^3 - 5x^{-3.5} + 3.5x^{-4.5}

Simplifying the expression:

dydx=20x35x3.5+3.5x4.5\frac{dy}{dx} = 20x^3 - \frac{5}{x^{3.5}} + \frac{3.5}{x^{4.5}}

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