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Sketch the graph of $y = 3^x$, $x \in \mathbb{R}$ showing the coordinates of any points at which the graph crosses the axes - Edexcel - A-Level Maths Pure - Question 10 - 2014 - Paper 1

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Sketch the graph of $y = 3^x$, $x \in \mathbb{R}$ showing the coordinates of any points at which the graph crosses the axes. Use algebra to solve the equation $... show full transcript

Worked Solution & Example Answer:Sketch the graph of $y = 3^x$, $x \in \mathbb{R}$ showing the coordinates of any points at which the graph crosses the axes - Edexcel - A-Level Maths Pure - Question 10 - 2014 - Paper 1

Step 1

Sketch the graph of $y = 3^x$

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Answer

To sketch the graph of the function y=3xy = 3^x, we start by identifying key coordinates.

  1. Intercepts:

    • Y-Intercept: When x=0x = 0, y=30=1y = 3^0 = 1. Thus, the graph crosses the y-axis at the point (0,1)(0, 1).
    • X-Intercept: The function does not cross the x-axis because 3x>03^x > 0 for all real xx.
  2. Behavior:

    • For large positive xx, the function y=3xy = 3^x will increase rapidly.
    • For large negative xx, the function approaches 00 but never touches the x-axis.

The graph is an increasing exponential curve starting from a value greater than zero as xx approaches negative infinity and rising steeply as xx becomes positive.

Step 2

Use algebra to solve the equation $3^{2x} - 9(3^x) + 18 = 0$

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Answer

To solve the equation, we can make a substitution:

Let y=3xy = 3^x, then 32x=y23^{2x} = y^2. The equation becomes:

y29y+18=0y^2 - 9y + 18 = 0

This is a quadratic equation in standard form. We can factor it:

(y6)(y3)=0(y - 6)(y - 3) = 0

Setting each factor to zero gives:

  1. y6=0    y=6y - 6 = 0 \implies y = 6
  2. y3=0    y=3y - 3 = 0 \implies y = 3

Now, we can revert back to xx:

  1. From y=6y = 6:
    3x=6    x=log363^x = 6 \implies x = \log_3{6}
    Approximating gives x1.631x \approx 1.631.

  2. From y=3y = 3:
    3x=3    x=13^x = 3 \implies x = 1.

Thus, the solutions are approximately:

  • x1.63x \approx 1.63
  • x=1x = 1.

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