Given that
$f(x) = \frac{1}{x}, \quad x \neq 0$,
(a) sketch the graph of $y = f(x) + 3$ and state the equations of the asymptotes - Edexcel - A-Level Maths Pure - Question 5 - 2007 - Paper 2
Question 5
Given that
$f(x) = \frac{1}{x}, \quad x \neq 0$,
(a) sketch the graph of $y = f(x) + 3$ and state the equations of the asymptotes.
(b) Find the coordinates of... show full transcript
Worked Solution & Example Answer:Given that
$f(x) = \frac{1}{x}, \quad x \neq 0$,
(a) sketch the graph of $y = f(x) + 3$ and state the equations of the asymptotes - Edexcel - A-Level Maths Pure - Question 5 - 2007 - Paper 2
Step 1
(a) sketch the graph of y = f(x) + 3 and state the equations of the asymptotes.
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Answer
To sketch the graph of y=f(x)+3, we first recognize that the base function f(x)=x1 has vertical asymptote at x=0 and a horizontal asymptote at y=0.
With the transformation applied, the graph shifts upward by 3 units. The new horizontal asymptote is now given by the equation:
y=3
The vertical asymptote remains unchanged at:
x=0
The overall structure of the graph retains two branches, one in the first quadrant and one in the fourth quadrant, without overlapping the asymptotes.
Step 2
(b) Find the coordinates of the point where y = f(x) + 3 crosses a coordinate axis.
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Answer
To find where the graph crosses the coordinate axes, we need to determine where:
The graph crosses the y-axis:
Set x=0:
The graph does not cross the y-axis due to the vertical asymptote.
The graph crosses the x-axis:
Set y=0:
0=x1+3
Rearranging gives: −3=x1
Thus, x=−31
Therefore, the coordinates where y=f(x)+3 crosses the x-axis are: (−31,0).