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9. Jess started work 20 years ago - Edexcel - A-Level Maths Pure - Question 1 - 2015 - Paper 1

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9. Jess started work 20 years ago. In year 1 her annual salary was £17000. Her annual salary increased by £1500 each year, so that her annual salary in year 2 was £1... show full transcript

Worked Solution & Example Answer:9. Jess started work 20 years ago - Edexcel - A-Level Maths Pure - Question 1 - 2015 - Paper 1

Step 1

Find the value of the constant k.

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Answer

To find the value of k, we first determine how many years it takes for Jess's salary to reach £32000 starting from £17000 with an annual increase of £1500.

  1. Establish the arithmetic sequence:

    • Year 1: £17000
    • Year 2: £18500
    • Year 3: £20000
    • So, the salary in year n can be expressed as: Sn=17000+(n1)×1500S_n = 17000 + (n - 1) \times 1500
  2. Set the equation to find k:

    • We need to find k such that: 17000+(k1)×1500=3200017000 + (k - 1) \times 1500 = 32000
    • Rearranging gives: (k1)×1500=3200017000(k - 1) \times 1500 = 32000 - 17000 (k1)×1500=15000(k - 1) \times 1500 = 15000
    • Dividing both sides by 1500: k1=10k - 1 = 10 k=11k = 11

Thus, the value of the constant k is 11.

Step 2

Calculate the total amount that Jess has earned in the 20 years.

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Answer

To calculate the total amount Jess has earned over 20 years, we will consider the first 11 years where her salary increases, and the last 9 years where she earns a fixed salary of £32000.

  1. Total Salary for the first 11 years:

    • Year 1: £17000
    • Year 2: £18500
    • Year 3: £20000
    • Year 4: £21500
    • Year 5: £23000
    • Year 6: £24500
    • Year 7: £26000
    • Year 8: £27500
    • Year 9: £29000
    • Year 10: £30500
    • Year 11: £32000

    The total for these 11 years can be calculated as: extTotal11=17000+18500+20000+21500+23000+24500+26000+27500+29000+30500+32000 ext{Total}_{11} = 17000 + 18500 + 20000 + 21500 + 23000 + 24500 + 26000 + 27500 + 29000 + 30500 + 32000 This is an arithmetic series where:

    • First term (a) = £17000
    • Last term (l) = £32000
    • Number of terms (n) = 11
    • Using the formula for the sum of an arithmetic series: Sn=n2(a+l)S_n = \frac{n}{2} (a + l) S11=112(17000+32000)=112×49000=269500S_{11} = \frac{11}{2} (17000 + 32000) = \frac{11}{2} \times 49000 = 269500
  2. Total Salary for the last 9 years:

    • For year 12 to 20, Jess earns a fixed salary of £32000.
    • Total for these 9 years: extTotal9=9×32000=288000 ext{Total}_{9} = 9 \times 32000 = 288000
  3. Combine the totals:

    • Total earnings over 20 years: extTotal20=extTotal11+extTotal9=269500+288000=557500 ext{Total}_{20} = ext{Total}_{11} + ext{Total}_{9} = 269500 + 288000 = 557500

Thus, the total amount that Jess has earned in 20 years is £557500.

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