Starting with the equation:
log2(x+1)−log2x=log27,
we can apply the properties of logarithms. This simplifies to:
log2(xx+1)=log27.
Setting the arguments equal gives us:
xx+1=7,
which leads to:
x+1=7x.
Solving for x, we get:
1=6x⇒x=61.
Thus, the solution is x=61.