Photo AI

The circle C with centre T and radius r has equation $$x^2 + y^2 - 20x - 16y + 139 = 0$$ (a) Find the coordinates of the centre of C - Edexcel - A-Level Maths Pure - Question 5 - 2012 - Paper 3

Question icon

Question 5

The-circle-C-with-centre-T-and-radius-r-has-equation--$$x^2-+-y^2---20x---16y-+-139-=-0$$--(a)-Find-the-coordinates-of-the-centre-of-C-Edexcel-A-Level Maths Pure-Question 5-2012-Paper 3.png

The circle C with centre T and radius r has equation $$x^2 + y^2 - 20x - 16y + 139 = 0$$ (a) Find the coordinates of the centre of C. (b) Show that r = 5. The li... show full transcript

Worked Solution & Example Answer:The circle C with centre T and radius r has equation $$x^2 + y^2 - 20x - 16y + 139 = 0$$ (a) Find the coordinates of the centre of C - Edexcel - A-Level Maths Pure - Question 5 - 2012 - Paper 3

Step 1

Find the perimeter of the sector PTQ.

96%

114 rated

Answer

To find the perimeter of the sector PTQ, we first need to calculate the length of the arc PQ and the radii TP and TQ.

  1. The arc length for angle heta=1.855 heta = 1.855 radians:

    • Arc length = rimesheta=5imes1.855=9.275.r imes heta = 5 imes 1.855 = 9.275.

  2. The total perimeter of the sector is:

    • Perimeter = Arc length + 2 * radius = 9.275+2∗5=19.275.9.275 + 2 * 5 = 19.275.

Thus, the perimeter of sector PTQ is approximately 19.27519.275.

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;