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A scientist is studying the number of bees and the number of wasps on an island - Edexcel - A-Level Maths Pure - Question 13 - 2022 - Paper 1

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A scientist is studying the number of bees and the number of wasps on an island. The number of bees, measured in thousands, $N_b$, is modelled by the equation $N_b ... show full transcript

Worked Solution & Example Answer:A scientist is studying the number of bees and the number of wasps on an island - Edexcel - A-Level Maths Pure - Question 13 - 2022 - Paper 1

Step 1

Find the number of bees at the start of the study

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Answer

To find the number of bees at the start of the study, we substitute t=0t = 0 into the equation:

Nb=45+220e0.6×0N_b = 45 + 220 e^{0.6 \times 0}

This simplifies to:

Nb=45+2201=265N_b = 45 + 220 \cdot 1 = 265

Thus, the number of bees at the start of the study is 265 thousand.

Step 2

Show that, exactly 10 years after the start of the study, the number of bees was increasing at a rate of approximately 18 thousand per year

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Answer

To find the rate of increase of bees at t=10t = 10, we first differentiate the bee model:

dNbdt=2200.6e0.6t\frac{dN_b}{dt} = 220 \cdot 0.6 e^{0.6t}

Substituting t=10t = 10 gives:

dNbdt=2200.6e0.6×10=132e6\frac{dN_b}{dt} = 220 \cdot 0.6 e^{0.6 \times 10} = 132 e^{6}

Calculating e6403.4288e^{6} \approx 403.4288, we have:

dNbdt132403.428853281.1\frac{dN_b}{dt} \approx 132 \cdot 403.4288 \approx 53281.1

Since this is in thousands, the rate is approximately:

53281.1100018\frac{53281.1}{1000} \approx 18

Thus, the number of bees was increasing at a rate of approximately 18 thousand per year.

Step 3

Find the value of T to 2 decimal places

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Answer

To find TT where the number of bees equals the number of wasps:

Set the equations equal to each other:

45+220e0.6T=10+800e0.6T45 + 220 e^{0.6T} = 10 + 800 e^{0.6T}

Rearranging gives:

220e0.6T800e0.6T=1045220 e^{0.6T} - 800 e^{0.6T} = 10 - 45

This simplifies to:

$$e^{0.6T} = \frac{35}{580} = \frac{7}{116}$$ Taking the natural logarithm of both sides: $$0.6T = \ln\left(\frac{7}{116}\right)$$ Thus: $$T = \frac{\ln\left(\frac{7}{116}\right)}{0.6}$$ Calculating this gives: $$T \approx 12.08$$ Therefore, the value of $T$ is approximately 12.08.

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