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By taking logarithms of both sides, solve the equation $$4^{3p-1} = 5^{210}$$ giving the value of $p$ to one decimal place. - Edexcel - A-Level Maths Pure - Question 4 - 2020 - Paper 1

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By taking logarithms of both sides, solve the equation $$4^{3p-1} = 5^{210}$$ giving the value of $p$ to one decimal place.

Worked Solution & Example Answer:By taking logarithms of both sides, solve the equation $$4^{3p-1} = 5^{210}$$ giving the value of $p$ to one decimal place. - Edexcel - A-Level Maths Pure - Question 4 - 2020 - Paper 1

Step 1

Taking logarithms of both sides

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Answer

To solve the equation, start by taking the logarithm of both sides:

log(43p1)=log(5210)\log(4^{3p-1}) = \log(5^{210})

Using the power rule of logarithms, this can be simplified to:

(3p1)log4=210log5(3p - 1) \log 4 = 210 \log 5

Step 2

Rearranging the equation

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Answer

Next, isolate pp by dividing both sides by log4\log 4:

3p1=210log5log43p - 1 = \frac{210 \log 5}{\log 4}

Then, add 1 to both sides:

3p=210log5log4+13p = \frac{210 \log 5}{\log 4} + 1

Step 3

Solving for p

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Answer

Finally, divide both sides by 3 to solve for pp:

p=13(210log5log4+1)p = \frac{1}{3} \left( \frac{210 \log 5}{\log 4} + 1 \right)

Now, calculating this with the values of log50.6990\log 5 \approx 0.6990 and log40.6021\log 4 \approx 0.6021:

  • First, calculate 210×0.69900.6021245.8\frac{210 \times 0.6990}{0.6021} \approx 245.8
  • Then, add 1: 245.8+1246.8245.8 + 1 \approx 246.8
  • Finally, divide by 3: 246.8382.3\frac{246.8}{3} \approx 82.3

Thus, the final value of p82.3p \approx 82.3, rounded to one decimal place.

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