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Find, giving your answer to 3 significant figures where appropriate, the value of x for which (a) $3^x = 5$ - Edexcel - A-Level Maths Pure - Question 4 - 2005 - Paper 2

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Find, giving your answer to 3 significant figures where appropriate, the value of x for which (a) $3^x = 5$. (b) $\log_2(2x + 1) - \log_2(x) = 2$.

Worked Solution & Example Answer:Find, giving your answer to 3 significant figures where appropriate, the value of x for which (a) $3^x = 5$ - Edexcel - A-Level Maths Pure - Question 4 - 2005 - Paper 2

Step 1

(a) $3^x = 5$

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Answer

To solve for xx, we can take the logarithm base 3 on both sides:

log3(3x)=log3(5)\log_3(3^x) = \log_3(5)

This simplifies to:

x=log3(5)x = \log_3(5)

Using the change of base formula:

x=log10(5)log10(3)x = \frac{\log_{10}(5)}{\log_{10}(3)}

Calculating this using a calculator, we find:

x1.464x \approx 1.464

Thus, to three significant figures, the value of xx is:

x1.46x \approx 1.46.

Step 2

(b) $\log_2(2x + 1) - \log_2(x) = 2$

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Answer

Using the properties of logarithms, we can combine the logarithms:

log2(2x+1x)=2\log_2\left(\frac{2x + 1}{x}\right) = 2

Exponentiating both sides gives:

2x+1x=22=4\frac{2x + 1}{x} = 2^2 = 4

Now, multiply both sides by xx to eliminate the fraction:

2x+1=4x2x + 1 = 4x

Rearranging yields:

1=4x2x1 = 4x - 2x

So:

2x=1x=12=0.52x = 1\quad \Rightarrow \quad x = \frac{1}{2} = 0.5

Therefore, the value of xx is:

x=0.5x = 0.5.

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