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A fair blue die has faces numbered 1, 1, 3, 3 and 5 - Edexcel - A-Level Maths Statistics - Question 6 - 2013 - Paper 1

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A fair blue die has faces numbered 1, 1, 3, 3 and 5. The random variable B represents the score when the blue die is rolled. (a) Write down the probability distribu... show full transcript

Worked Solution & Example Answer:A fair blue die has faces numbered 1, 1, 3, 3 and 5 - Edexcel - A-Level Maths Statistics - Question 6 - 2013 - Paper 1

Step 1

Write down the probability distribution for B.

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Answer

The probability distribution for B, representing the score when the blue die is rolled, is as follows:

b135
P(B = b)2/52/51/5

Step 2

State the name of this probability distribution.

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Answer

This distribution is named a Discrete Uniform Distribution.

Step 3

Write down the value of E(B).

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Answer

The expected value E(B) can be calculated as: E(B) = rac{1}{5}(1 + 1 + 3 + 3 + 5) = rac{13}{5} = 2.6

Step 4

Find E(R).

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Answer

To find E(R), we use the formula: E(R) = rac{2}{3} imes 2 + rac{1}{6} imes 4 + rac{1}{6} imes 6 = rac{4}{3} + rac{2}{6} + 1 = rac{4}{3} + rac{1}{3} + rac{3}{3} = rac{8}{3}

Step 5

Find Var(R).

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Answer

To find Var(R), we first compute E(R²): E(R²) = rac{2}{3}(2^2) + rac{1}{6}(4^2) + rac{1}{6}(6^2) = rac{2}{3}(4) + rac{1}{6}(16) + rac{1}{6}(36) = rac{8}{3} + rac{16}{6} + rac{36}{6}

Next, simplify: E(R²) = rac{8}{3} + rac{8}{3} + 6 = rac{34}{3}

Therefore, Var(R) = E(R²) - (E(R))^2 = rac{34}{3} - rac{64}{9} = rac{34 imes 3 - 64}{9} = rac{102 - 64}{9} = rac{38}{9}

Step 6

Find the probability that Avisha wins the game, stating clearly which die she uses in each case.

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Answer

Avisha's winning probabilities depend on the coin flip. If 2 appears, she chooses the blue die:

  • Probability (choosing blue die) = 12\frac{1}{2}, winning probability = 25\frac{2}{5}.

If 5 appears, she chooses the red die:

  • Probability (choosing red die) = 12\frac{1}{2}, winning probability = 23\frac{2}{3}.

Thus, total probability that Avisha wins: P(Avisha wins)=12×25+12×23=15+13=315+515=815P(Avisha \ wins) = \frac{1}{2} \times \frac{2}{5} + \frac{1}{2} \times \frac{2}{3} = \frac{1}{5} + \frac{1}{3} = \frac{3}{15} + \frac{5}{15} = \frac{8}{15}

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