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The random variable Y has a normal distribution with mean µ and standard deviation σ - Edexcel - A-Level Maths: Statistics - Question 3 - 2018 - Paper 1

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The random variable Y has a normal distribution with mean µ and standard deviation σ. The P(Y > 17) = 0.4. Find (a) P(µ < Y < 17) (b) P(µ - σ < Y < 17)

Worked Solution & Example Answer:The random variable Y has a normal distribution with mean µ and standard deviation σ - Edexcel - A-Level Maths: Statistics - Question 3 - 2018 - Paper 1

Step 1

P(µ < Y < 17)

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Answer

To find the probability P(µ < Y < 17), we start with the given information that P(Y > 17) = 0.4.

Using the properties of the normal distribution, we know that:

P(Y<17)=1P(Y>17)=10.4=0.6P(Y < 17) = 1 - P(Y > 17) = 1 - 0.4 = 0.6

Next, since the mean µ is where the distribution centers, we can standardize it. The area to the left of µ is also half of the total area, thus this gives:

P(µ<Y<17)=P(Y<17)P(Y<µ)=0.60.5=0.1P(µ < Y < 17) = P(Y < 17) - P(Y < µ) = 0.6 - 0.5 = 0.1

Step 2

P(µ - σ < Y < 17)

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Answer

For the second part, we need to calculate P(µ - σ < Y < 17).

We standardize the variable Y:

Let Z = (Y - µ) / σ.

Then,

( Y < 17 \implies Z < \frac{17 - µ}{σ} )

We need to evaluate ( P(Z < \frac{17 - µ}{σ}) ).

From the first part, we calculated that ( P(Y < 17) = 0.6 ).

Now, we will find P(Y < µ - σ):

Since P(Y > 17) = 0.4, this implies:

P(Y<µσ)=P(Y<17)P(µσ<Y<17)P(Y < µ - σ) = P(Y < 17) - P(µ - σ < Y < 17)

Calculating yields:

  1. Set ( P(Y < µ - σ) \approx 0.158 ) (from standard normal distribution table) joint with previous steps, we have:

P(µσ<Y<17)=P(Y<17)P(Y<µσ)=0.60.158=0.441P(µ - σ < Y < 17) = P(Y < 17) - P(Y < µ - σ) = 0.6 - 0.158 = 0.441

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