Photo AI

In a quiz, a team gains 10 points for every question it answers correctly and loses 5 points for every question it does not answer correctly - Edexcel - A-Level Maths Statistics - Question 5 - 2015 - Paper 1

Question icon

Question 5

In-a-quiz,-a-team-gains-10-points-for-every-question-it-answers-correctly-and-loses-5-points-for-every-question-it-does-not-answer-correctly-Edexcel-A-Level Maths Statistics-Question 5-2015-Paper 1.png

In a quiz, a team gains 10 points for every question it answers correctly and loses 5 points for every question it does not answer correctly. The probability of answ... show full transcript

Worked Solution & Example Answer:In a quiz, a team gains 10 points for every question it answers correctly and loses 5 points for every question it does not answer correctly - Edexcel - A-Level Maths Statistics - Question 5 - 2015 - Paper 1

Step 1

Show that the probability of scoring 15 points in a round is 0.432.

96%

114 rated

Answer

To score 15 points, a team must answer 2 questions correctly and 1 incorrectly. The probability can be calculated using the combination formula and the given probabilities:

  1. The probability of answering a question correctly is 0.6 and incorrectly is 0.4.
  2. The number of ways to choose which 2 out of 3 questions are answered correctly is given by: (32)=3\binom{3}{2} = 3
  3. Thus, the probability of scoring 15 points is: P(X=15)=3×(0.6)2×(0.4)=3×0.36×0.4=0.432P(X=15) = 3 \times (0.6)^2 \times (0.4) = 3 \times 0.36 \times 0.4 = 0.432 Hence, the probability of scoring 15 points in a round is confirmed to be 0.432.

Step 2

Find the probability of scoring 0 points in a round.

99%

104 rated

Answer

To score 0 points, a team must answer all 3 questions incorrectly. The probability of scoring 0 points can be calculated as follows:

  1. Since the probability of answering incorrectly is 0.4, the probability of scoring 0 points is: P(X=0)=(0.4)3=0.064P(X=0) = (0.4)^3 = 0.064

Step 3

Find the probability of scoring a total of 30 points in 2 rounds.

96%

101 rated

Answer

To score a total of 30 points in 2 rounds, a team must score 30 points in one round and 0 points in the other round. We can calculate this as follows:

  1. The probability of scoring 30 points (3 correct answers) in one round is: P(X=30)=(0.6)3=0.216P(X=30) = (0.6)^3 = 0.216
  2. Therefore, the probability of scoring 0 points in the other round is: P(X=0)=0.064P(X=0) = 0.064
  3. Since these events are independent, the probability of scoring 30 points in one round and 0 in another is: P(X=30 in 1st round and X=0 in 2nd round)=0.216×0.064=0.013824P(X=30 \text{ in 1st round} \text{ and } X=0 \text{ in 2nd round}) = 0.216 \times 0.064 = 0.013824

Step 4

Find E(X).

98%

120 rated

Answer

The expected value E(X) can be computed using the formula: E(X)=(xP(X=x))E(X) = \sum (x \cdot P(X=x))

  1. Substituting the probabilities we have: E(X)=(30×0.216)+(15×0.432)+(0×0.288)+(15×0.064)E(X) = (30 \times 0.216) + (15 \times 0.432) + (0 \times 0.288) + (-15 \times 0.064)
  2. Calculating each term:
    • 30×0.216=6.4830 \times 0.216 = 6.48
    • 15×0.432=6.4815 \times 0.432 = 6.48
    • 0×0.288=00 \times 0.288 = 0
    • 15×0.064=0.96-15 \times 0.064 = -0.96
  3. Summing these values gives: E(X)=6.48+6.48+00.96=12E(X) = 6.48 + 6.48 + 0 - 0.96 = 12

Step 5

Find Var(X).

97%

117 rated

Answer

The variance Var(X) can be calculated using the formula:

Var(X)=E(X2)(E(X))2Var(X) = E(X^2) - (E(X))^2

  1. First, calculate E(X2)E(X^2): E(X2)=(302×0.216)+(152×0.432)+(02×0.288)+((15)2×0.064)E(X^2) = (30^2 \times 0.216) + (15^2 \times 0.432) + (0^2 \times 0.288) + ((-15)^2 \times 0.064)
    • 302×0.216=194.430^2 \times 0.216 = 194.4
    • 152×0.432=97.215^2 \times 0.432 = 97.2
    • 02×0.288=00^2 \times 0.288 = 0
    • (15)2×0.064=14.4(-15)^2 \times 0.064 = 14.4
  2. Adding these: E(X2)=194.4+97.2+0+14.4=306E(X^2) = 194.4 + 97.2 + 0 + 14.4 = 306
  3. Now, substituting back: Var(X)=306(12)2=306144=162Var(X) = 306 - (12)^2 = 306 - 144 = 162

Step 6

Find the expected number of points scored in the bonus round.

97%

121 rated

Answer

In the bonus round, the scoring system changes. The expected score can be determined similarly:

  1. Let Y be the number of points scored in the bonus round, where the probabilities are:
    • Correct answers: 20 points
    • Incorrect answers: -5 points
  2. With 3 questions, the probability distribution becomes:
    • Correct 3, Incorrect 0: P(Y=60)=(0.6)3=0.216P(Y=60) = (0.6)^3 = 0.216
    • Correct 2, Incorrect 1: P(Y=40)=3×(0.6)2×(0.4)=3×0.36×0.4=0.432P(Y=40) = 3 \times (0.6)^2 \times (0.4) = 3 \times 0.36 \times 0.4 = 0.432
    • Correct 1, Incorrect 2: P(Y=20)=3×(0.6)×(0.4)2=3×0.6×0.16=0.288P(Y=20) = 3 \times (0.6) \times (0.4)^2 = 3 \times 0.6 \times 0.16 = 0.288
    • Correct 0, Incorrect 3: P(Y=15)=(0.4)3=0.064P(Y=-15) = (0.4)^3 = 0.064
  3. Thus: E(Y)=(60×0.216)+(40×0.432)+(20×0.288)+(15×0.064)E(Y) = (60 \times 0.216) + (40 \times 0.432) + (20 \times 0.288) + (-15 \times 0.064) E(Y)=12.96+17.28+5.760.96=34.04E(Y) = 12.96 + 17.28 + 5.76 - 0.96 = 34.04

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;