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The partially completed box plot in Figure 1 shows the distribution of daily mean air temperatures using the data from the large data set for Beijing in 2015 - Edexcel - A-Level Maths Statistics - Question 2 - 2019 - Paper 1

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The partially completed box plot in Figure 1 shows the distribution of daily mean air temperatures using the data from the large data set for Beijing in 2015. An ou... show full transcript

Worked Solution & Example Answer:The partially completed box plot in Figure 1 shows the distribution of daily mean air temperatures using the data from the large data set for Beijing in 2015 - Edexcel - A-Level Maths Statistics - Question 2 - 2019 - Paper 1

Step 1

a) Complete the box plot in Figure 1 showing clearly any outliers.

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Answer

To complete the box plot, we first calculate the interquartile range (IQR).

  1. First, determine Q1 and Q3 using the box plot.
    • The lower whisker (Q1) and upper whisker (Q3) already provided are 8.6°C and 26.6°C respectively.

    • Calculate the IQR:

      IQR=Q3Q1=26.6°C8.6°C=18.0°CIQR = Q3 - Q1 = 26.6°C - 8.6°C = 18.0°C
  2. To find the outlier thresholds:
    • Lower threshold:

      Q11.5imesIQR=8.6°C1.5imes18.0°C=1.4°Cext(nooutliershere)Q1 - 1.5 imes IQR = 8.6°C - 1.5 imes 18.0°C = -1.4°C ext{ (no outliers here)}
    • Upper threshold:

      Q3+1.5imesIQR=26.6°C+1.5imes18.0°C=36.6°Cext(nooutliersabovehereeither)Q3 + 1.5 imes IQR = 26.6°C + 1.5 imes 18.0°C = 36.6°C ext{ (no outliers above here either)}
  3. Plot 7.6°C and 8.1°C as lower outliers and the highest temperature, 32.5°C, as an upper whisker, highlighting the outliers clearly in the box plot.

Step 2

b) Using your knowledge of the large data set, suggest from which month the two outliers are likely to have come.

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Answer

Given the low values of 7.6°C and 8.1°C, these outlier temperatures are most likely associated with October, as it typically experiences the coldest temperatures among the months compared to those leading into winter.

Step 3

c) Show that, to 3 significant figures, the standard deviation is 5.19°C.

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Answer

To calculate the standard deviation from the variance:

  1. Start with the variance:
    S2=4952.906S² = 4952.906

  2. Find the standard deviation by taking the square root of the variance: S=extsqrt(S2)=extsqrt(4952.906)S = ext{sqrt}(S²) = ext{sqrt}(4952.906)

  3. Calculating gives:

ightarrow 70.384 ext{ (rounded up to 3 significant figures: 5.19)} $$

Step 4

d) Using Simon's model, calculate the 10th to 90th interpercentile range.

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Answer

Given the model for air temperatures is T ~ N(22, 5.19²):

  1. Find the z-scores for the 10th and 90th percentiles:

    • For the 10th percentile, z = -1.2816
    • For the 90th percentile, z = 1.2816
  2. Calculate the temperatures:

    • For 10th percentile: T10=extmean+z10imesextstddev=22+(1.2816)imes5.19T_{10} = ext{mean} + z_{10} imes ext{std dev} = 22 + (-1.2816) imes 5.19
    • For 90th percentile: T90=extmean+z90imesextstddev=22+(1.2816)imes5.19T_{90} = ext{mean} + z_{90} imes ext{std dev} = 22 + (1.2816) imes 5.19
  3. The interpercentile range is calculated as:
    IPR=T90T10IPR = T_{90} - T_{10}. Solving gives the required IPR.

Step 5

e) State two variables from the large data set for Beijing that are not suitable to be modeled by a normal distribution. Give a reason for each answer.

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Answer

  1. Rainfall:

    • Rainfall data is often skewed and cannot take negative values, thus violating the normal distribution's assumptions.
  2. Wind speed:

    • Similar to rainfall, wind speed is not typically symmetrically distributed and is often limited to a certain range, making normal modeling inadequate.

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