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Question 2
An estate agent is studying the cost of office space in London. He takes a random sample of 90 offices and calculates the cost, £x per square foot. His results are g... show full transcript
Step 1
Answer
To find the width of the bar for the interval 20 ≤ x < 40, we note that the range is from 20 to 40, giving:
Width = 40 - 20 = 20 units.
Since the area of the bar representing the frequency of offices is equal to 16 cm² for 32 offices, we set up the equation:
Area = width × height = 16 cm²
Thus, 20 cm × height = 16 cm²,
Solving for height, we find:
Height = ( \frac{16}{20} = 0.8 : \text{cm} ).
Step 2
Answer
To estimate the median cost, we find the cumulative frequency. The total number of offices is 90, so the median position is ( \frac{90}{2} = 45 ). The cumulative frequency leads us to:
The median falls within the interval of 45 ≤ x < 50. Using linear interpolation between the midpoints of the cumulative frequencies:
Median = 45 + ( \frac{45 - 25}{50 - 25} \times (47.5 - 45) = 45 + 0.8 = 45.8 ).
Step 3
Answer
To calculate the mean cost, use the formula:
( \text{Mean} = \frac{\sum (f \cdot y)}{\sum f} )
Calculating ( \sum (f \cdot y) ):
Thus, ( \sum (f \cdot y) = 360 + 552.5 + 1187.5 + 1760 + 560 = 3920 )
Now, ( \text{Mean} = \frac{3920}{90} \approx 43.56 ).
Step 4
Answer
The standard deviation (SD) is calculated using the following formula:
( SD = \sqrt{\frac{\sum (f \cdot (y - \text{mean})^2)}{\sum f}} )
First, we find the variance:
Variance = ( \frac{(12(30-43.56)^2 + 13(42.5-43.56)^2 + 25(47.5-43.56)^2 + 32(55-43.56)^2 + 8(70-43.56)^2)}{90} )
Calculate the terms:
Finally, obtain ( SD = awrt 10.3 ).
Step 5
Answer
The data shows a slightly negative skewness since the mean (approximately 43.56) is less than the median (approximately 45.8). This indicates that there are a few lower-cost offices pulling the mean down, leading to a leftward tail in the distribution.
Step 6
Answer
Rika's suggestion of a normal distribution may not be entirely accurate considering the left skew observed. The data appears to be skewed rather than symmetrical, implying that a normal distribution might not fit well unless adjusted for the skewness.
Step 7
Answer
To find the 80th percentile using Rika's normal distribution (mean = £50, SD = £10):
Using the Z-score corresponding to 80th percentile, Z = 0.8416:
80th percentile = ( \text{Mean} + Z \cdot \text{SD} = 50 + 0.8416 \cdot 10 \approx 58.42 ).
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