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A midwife records the weights, in kg, of a sample of 50 babies born at a hospital - Edexcel - A-Level Maths Statistics - Question 5 - 2016 - Paper 1

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A midwife records the weights, in kg, of a sample of 50 babies born at a hospital. Her results are given in the table below. Weight (w kg) Frequency (f) Weight mi... show full transcript

Worked Solution & Example Answer:A midwife records the weights, in kg, of a sample of 50 babies born at a hospital - Edexcel - A-Level Maths Statistics - Question 5 - 2016 - Paper 1

Step 1

Calculate the width and height of the bar representing a weight of 3 ≤ w < 3.5.

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Answer

The width of the bar can be calculated as the difference between the upper and lower bounds of the weight interval:

Width=3.53=0.5 kg\text{Width} = 3.5 - 3 = 0.5 \text{ kg}

The height can be determined from the frequency of the weight interval. From the table, the frequency for this interval is 17. The height of the bar in the histogram is proportional to the frequency divided by the width of the interval:

Height=FrequencyWidth=170.5=34 cm\text{Height} = \frac{\text{Frequency}}{\text{Width}} = \frac{17}{0.5} = 34 \text{ cm}

Step 2

Use linear interpolation to estimate the median weight of these babies.

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Answer

To estimate the median weight, first, determine the cumulative frequency. The total number of babies is 50, so the median is the 25th baby. From the cumulative frequencies:

  • 1 baby (0 ≤ w < 2)
  • 9 babies (0 ≤ w < 3)
  • 26 babies (0 ≤ w < 3.5)

The median falls in the interval of 3 ≤ w < 3.5. To find its exact position:

Using linear interpolation:

Median=3+(252617)×(3.53)=3+(117)×0.5\text{Median} = 3 + \left( \frac{25 - 26}{17} \right) \times (3.5 - 3) = 3 + \left( \frac{-1}{17} \right) \times 0.5

Calculating this gives:

Median30.02943.0006 kg\text{Median} \approx 3 - 0.0294 \approx 3.0006 \text{ kg}

Step 3

Show that an estimate of the mean weight of these babies is 3.43 kg.

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Answer

To calculate the mean weight, use the formula:

Mean=(fx)N\text{Mean} = \frac{\sum (f \cdot x)}{N}

Where:

  • f is the frequency of each weight interval,
  • x is the weight midpoint,
  • N is the total frequency (50).

Calculating the contributions:

(fx)=(11)+(82.5)+(173.25)+(173.75)+(74.5)\sum (f \cdot x) = (1 \cdot 1) + (8 \cdot 2.5) + (17 \cdot 3.25) + (17 \cdot 3.75) + (7 \cdot 4.5)

This equates to:

=1+20+55.25+63.75+31.5=171.5= 1 + 20 + 55.25 + 63.75 + 31.5 = 171.5

Thus:

Mean=171.550=3.43 kg\text{Mean} = \frac{171.5}{50} = 3.43 \text{ kg}

Step 4

Find an estimate of the standard deviation of the weights of these babies.

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Answer

The standard deviation can be estimated using:

SD=f(xMean)2NSD = \sqrt{\frac{\sum f (x - \text{Mean})^2}{N}}

Calculating:

  1. Find (xMean)2(x - \text{Mean})^2 for each interval,
  2. Multiply by frequency and sum.

After calculating, using the estimate of the mean:

  1. Compute the sum of squares.
  2. Finally divide by N and take the square root to find SD.

This gives:

SD0.68 kgSD \approx 0.68 \text{ kg}

Step 5

Find P(W < 3)

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Answer

To find the probability:

P(W<3)=P(Z<33.430.65)P(W < 3) = P\left(Z < \frac{3 - 3.43}{0.65}\right)

Calculating the Z-score:

Z=0.430.650.6615Z = \frac{-0.43}{0.65} \approx -0.6615

Using Z-tables:

P(Z<0.6615)0.2546 or 0.254 (in decimal form)P(Z < -0.6615) \approx 0.2546 \text{ or } 0.254 \text{ (in decimal form)}

Step 6

With reference to your answers to (b), (c)(i) and comment on Shyam’s decision.

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Answer

Referring to the median, mean, and standard deviation:

  • The median estimated (3.0006 kg) is lower than the mean (3.43 kg), potentially indicating a right-skewed distribution.
  • Shyam’s model assumes a normal distribution, which may not accurately reflect the data as it's skewed.

Thus, his use of a normal distribution could lead to inaccurate predictions.

Step 7

Without carrying out any further calculations, state, giving a reason, what effect the addition of this newborn baby to the sample would have on your estimate of the (i) mean,

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Answer

The addition of a baby weighing 3.43 kg will not change the mean, as it equals the current mean of the sample. Thus, it remains 3.43 kg.

Step 8

(ii) standard deviation.

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Answer

The standard deviation will decrease because adding a data point that is equal to the mean reduces the spread of the data. New data points that are closer to the mean typically decrease standard deviation.

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