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There are four forces acting on an aeroplane in flight, as shown - Edexcel - A-Level Physics - Question 13 - 2023 - Paper 4

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There are four forces acting on an aeroplane in flight, as shown. (a) The lift force is perpendicular to the wings. To change direction, the aeroplane ‘banks’ so t... show full transcript

Worked Solution & Example Answer:There are four forces acting on an aeroplane in flight, as shown - Edexcel - A-Level Physics - Question 13 - 2023 - Paper 4

Step 1

Show that the radius of the circular path is about 800 m.

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Answer

To determine the radius of the circular path, we first need to identify the forces acting on the aeroplane. The weight (W) of the aeroplane can be calculated using the formula:

W=mgW = mg

Where:

  • m=1200extkgm = 1200 ext{ kg} (mass of the aeroplane)
  • g=9.81extm/s2g = 9.81 ext{ m/s}^2 (acceleration due to gravity)

Substituting values: W=1200extkgimes9.81extm/s2=11772extNW = 1200 ext{ kg} imes 9.81 ext{ m/s}^2 = 11772 ext{ N}

The lift force (L) can be calculated using suitable trigonometry considering the angle of bank (20°). The vertical component of the lift must counteract the weight:

Limesextcos(20°)=WL imes ext{cos}(20°) = W

Thus, L=Wcos(20°)=11772cos(20°)12572extNL = \frac{W}{\cos(20°)} = \frac{11772}{\cos(20°)} \\ \approx 12572 ext{ N}

Now using the centripetal force formula, we have: L=mv2rL = \frac{mv^2}{r}

Rearranging for radius (r): r=mv2Lr = \frac{mv^2}{L}

Substituting:

  • m=1200extkgm = 1200 ext{ kg}
  • v=54extm/sv = 54 ext{ m/s}
  • L12572extNL \approx 12572 ext{ N}

r=1200imes(54)212572813.56extmr = \frac{1200 imes (54)^2}{12572} \approx 813.56 ext{ m}

Thus, the radius of the circular path is approximately 800 m.

Step 2

Determine the time taken by the plane to move through 90° of the circular path.

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Answer

To calculate the time taken to travel through 90° of the circular path, we known the formula:

t=θωt = \frac{\theta}{\omega}

Where:

  • heta=π2 radians=90° heta = \frac{\pi}{2} \text{ radians} = 90°
  • extTheangularvelocity,ω=vr ext{The angular velocity,} \omega = \frac{v}{r} where vv is the linear speed and rr is the radius calculated previously.

From the first part:

  • r816mr \approx 816 m
  • v=54extm/sv = 54 ext{ m/s}

Now, ω=54816 rad/s0.066extrad/s\omega = \frac{54}{816} \text{ rad/s} \approx 0.066 ext{ rad/s}

Substituting into the time formula: t=π20.06624extst = \frac{\frac{\pi}{2}}{0.066} \approx 24 ext{ s}

So, it takes approximately 24 seconds to travel through 90°.

Step 3

Explain what will happen to the vertical motion of the aeroplane.

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Answer

When the wings of the aeroplane are levelled, the vertical component of the lift force is equal to that of the weight. Therefore, with the lift force remaining constant while banking ceases:

  • The resultant upwards force is now balanced with the weight of the aeroplane.
  • Thus, there will be no net vertical motion, meaning the aeroplane will maintain its altitude.

However, if at any time the lift force exceeds the weight, the aeroplane will start to ascend. Conversely, if the lift is less than the weight, the aeroplane will descend.

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