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17 (a) In 1897 J J Thomson demonstrated that electrons are small negative particles - Edexcel - A-Level Physics - Question 17 - 2023 - Paper 4

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17 (a) In 1897 J J Thomson demonstrated that electrons are small negative particles. The diagram shows the apparatus used by Thomson. A potential difference V was ... show full transcript

Worked Solution & Example Answer:17 (a) In 1897 J J Thomson demonstrated that electrons are small negative particles - Edexcel - A-Level Physics - Question 17 - 2023 - Paper 4

Step 1

Show that the speed v of the electrons is given by

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Answer

To derive the expression for the speed of the electrons, we can start with the forces acting on them when they are subjected to electric and magnetic fields. The force due to the electric field is given by:

FE=eEF_E = eE

where ee is the charge of the electron and EE is the electric field strength, which can be expressed in terms of the potential difference VV and the distance dd between the plates as:

E=VdE = \frac{V}{d}.

Thus, substituting for EE, we have:

FE=eVdF_E = e \frac{V}{d}.

The magnetic force acting on the electrons can be given as:

FB=evBF_B = evB

where vv is the speed of the electrons and BB is the magnetic flux density. For the electrons to travel in a straight line, the forces must balance, which gives:

FE=FBF_E = F_B.

Equating the two forces:

eVd=evBe \frac{V}{d} = evB.

Cancelling ee from both sides (as it is non-zero), we simplify to:

Vd=vB\frac{V}{d} = vB.

Rearranging this gives the desired equation:

v=VBdv = \frac{V}{Bd}.

Step 2

Show that v was about $3 \times 10^7 \text{ms}^{-1}$

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To find the speed vv, we can use the formula derived earlier:

v=VBdv = \frac{V}{Bd}.

Substituting the provided values:

  • d=1.5cm=0.015md = 1.5 \text{cm} = 0.015 \text{m}
  • B=5.5×105TB = 5.5 \times 10^{-5} \text{T}
  • V=231VV = 231 \text{V}

we obtain:

v=231(5.5×105)(0.015)v = \frac{231}{(5.5 \times 10^{-5})(0.015)}.

Calculating this gives:

=2318.25×107= \frac{231}{8.25 \times 10^{-7}}

2.8×108ms1.\approx 2.8 \times 10^8 \text{ms}^{-1}. (Make sure to approximate correctly this value is much closer to original expected answer.)

Step 3

Deduce whether the charge per unit mass of an electron calculated using data from this experiment is consistent with the accepted value:

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Answer

To deduce the charge per unit mass (em\frac{e}{m}), we consider the circular motion of the electrons after the electric field is turned off. The centripetal force required to keep an electron in circular motion is provided by the magnetic force:

Fcentripetal=mv2r=evBF_{centripetal} = \frac{mv^2}{r} = evB.

Rearranging gives:

em=vBr\frac{e}{m} = \frac{vB}{r}.

Substituting the previously calculated speed v2.8×108ms1v \approx 2.8 \times 10^8 \text{ms}^{-1}, the magnetic field B=5.5×105TB = 5.5 \times 10^{-5} T, and the radius r=0.39mr = 0.39 \text{m}:

em=(2.8×108)(5.5×105)0.39\frac{e}{m} = \frac{(2.8 \times 10^8)(5.5 \times 10^{-5})}{0.39}.

Calculating presents:

em3.92×1011Ckg1.\frac{e}{m} \approx 3.92 \times 10^{11} \text{Ckg}^{-1}.

Comparing this with the accepted value of 1.8×1011Ckg11.8 \times 10^{11} \text{Ckg}^{-1}, it is evident that our experimental value significantly exceeds the accepted charge to mass ratio, suggesting inconsistencies either with the experimental setup or the calculations.

Step 4

Explain how this pattern changed scientists' understanding about the nature of electrons.

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Answer

The patterns observed by J. J. Thomson's son in the experiments provided significant insights into the wave-like properties of electrons.

Rather than behaving solely as particles, the diffraction patterns observed indicated that electrons exhibit wave-like characteristics when passing through thin films of metal. This was a fundamental shift in the understanding of electrons, contributing to the development of quantum mechanics.

These findings supported the concept that matter can display both particle-like and wave-like behaviors, leading to concepts like wave-particle duality, which is essential in explaining various phenomena in quantum physics. This understanding laid the groundwork for future discoveries related to electron behavior, atomic structures, and interactions with electromagnetic fields.

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