A ball is thrown vertically upwards at a velocity of 6.0 ms^-1 - Edexcel - A-Level Physics - Question 8 - 2023 - Paper 1

To find the maximum height reached by the ball when thrown upwards, we can use the formula derived from the equations of motion:

$h = \frac{v^{2}}{2g}$

where:

• ( v = 6.0 ) m/s (initial velocity)
• ( g = 9.81 ) m/s² (acceleration due to gravity)

Substituting the values:

$h = \frac{(6.0)^{2}}{2 \times 9.81}$

Evaluating this gives:

$h = \frac{36.0}{19.62} \approx 1.836$

Thus, the correct choice for the formula that gives the maximum height is option A: ( \frac{6.0^{2}}{2 \times 9.81} ).