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Question 10
A model rocket accelerates vertically upwards then decelerates due to gravity until it reaches a maximum height. (a) A velocity-time graph for the rocket until it r... show full transcript
Step 1
Answer
To find the maximum height of the rocket, we need to calculate the area under the velocity-time graph.
The area under the graph between time 0 to 2 seconds (where the rocket is ascending) forms a triangle. The base of this triangle is the time interval of 2 seconds and the height is the maximum velocity of 30 m/s.
Using the formula for the area of a triangle:
we have:
Next, for the time interval of 2 to 4 seconds (where the rocket is descending), the area forms a rectangle with a width of 2 seconds and a height of 30 m/s:
Adding both areas together:
As gravitational deceleration affects the total height gained, we must use the net effect. Therefore, the total height is slightly less than this, and thus:
This confirms that the rocket reaches a maximum height of approximately 68 m.
Step 2
Answer
After the parachute opens, the rocket achieves a terminal velocity of 2.0 m/s almost instantly. This means the rocket will then have a horizontal line on the velocity-time graph from time = 4 seconds down to the time when it reaches the ground; the velocity remains constant at 2.0 m/s, reflecting the parachute's effect until the ground is reached.
Step 3
Answer
To find the resultant velocity of the rocket, we need to combine the vertical and horizontal components of the velocity.
The vertical velocity is 2.0 m/s downward and the horizontal velocity is 1.5 m/s. We can use the Pythagorean theorem to find the magnitude of the resultant velocity:
Substituting the values gives:
To determine the direction, we can use trigonometry:
Thus, the velocity of the rocket can be represented as a vector at an angle of approximately 53° to the horizontal.
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