Photo AI

A student plans an investigation using mould - AQA - GCSE Biology - Question 4 - 2018 - Paper 1

Question icon

Question 4

A-student-plans-an-investigation-using-mould-AQA-GCSE Biology-Question 4-2018-Paper 1.png

A student plans an investigation using mould. Mould spores are hazardous. Give one safety precaution the student should take when doing this investigation. ... show full transcript

Worked Solution & Example Answer:A student plans an investigation using mould - AQA - GCSE Biology - Question 4 - 2018 - Paper 1

Step 1

Mould spores are hazardous. Give one safety precaution the student should take when doing this investigation.

96%

114 rated

Answer

The student should wear a face mask to avoid inhaling the harmful mould spores.

Step 2

Describe how the materials and equipment could be used to test the hypothesis.

99%

104 rated

Answer

To test the hypothesis, the student would follow these steps:

  1. Cut a specified number of slices of bread to the same size.
  2. Place the same number of mould spores on each slice of bread to ensure consistency.
  3. Seal each slice in different sealable plastic bags.
  4. Place the bags in different controlled environments, such as a refrigerator, room temperature, and an incubator to test various temperatures.
  5. Leave each bread sample for a set amount of time to allow mould growth.
  6. Measure the amount of mould growth on each slice after the incubation period and compare results to determine how temperature affects mould growth.

Step 3

Give one variable the student should control in the investigation.

96%

101 rated

Answer

The student should control the amount of mould spores used on each slice of bread to ensure that the results are consistent and reliable.

Step 4

Determine the rate of mould growth at 42 °C between day 2 and day 7.

98%

120 rated

Answer

To determine the rate of mould growth at 42 °C, observe the amount of mould on day 2 and on day 7 from Figure 3.
If the amount of mould on day 2 is 10 units and on day 7 is 52 units, the rate of growth can be calculated as follows:
extRateofgrowth=(5210)(72)=425=8.4 units per dayext{Rate of growth} = \frac{(52 - 10)}{(7 - 2)} = \frac{42}{5} = 8.4 \text{ units per day}

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;