Photo AI

Potassium sulfate contains K<sup>+</sup> and SO<sub>4</sub><sup>2-</sup> ions - AQA - GCSE Chemistry Combined Science - Question 2 - 2022 - Paper 1

Question icon

Question 2

Potassium-sulfate-contains-K<sup>+</sup>-and-SO<sub>4</sub><sup>2-</sup>-ions-AQA-GCSE Chemistry Combined Science-Question 2-2022-Paper 1.png

Potassium sulfate contains K<sup>+</sup> and SO<sub>4</sub><sup>2-</sup> ions. What is the formula of potassium sulfate? Tick (✔) one box. KSO<sub>4</sub> K<sub>2... show full transcript

Worked Solution & Example Answer:Potassium sulfate contains K<sup>+</sup> and SO<sub>4</sub><sup>2-</sup> ions - AQA - GCSE Chemistry Combined Science - Question 2 - 2022 - Paper 1

Step 1

What is the formula of potassium sulfate?

96%

114 rated

Answer

The formula for potassium sulfate is K<sub>2</sub>SO<sub>4</sub>.

Step 2

What are the volumes of gases collected in the electrolysis experiment?

99%

104 rated

Answer

According to Figure 2, the volume of hydrogen collected is 30 cm<sup>3</sup> and the volume of oxygen collected is 15 cm<sup>3</sup>.

Step 3

Explain how the volumes of gases collected in the experiment in Figure 2 support the student's hypothesis.

96%

101 rated

Answer

The volumes of hydrogen and oxygen collected are in a 2:1 ratio, which reflects the molecular ratio of hydrogen to oxygen in water (H<sub>2</sub>O). This supports the student's hypothesis, as 2 volumes of hydrogen are produced for every 1 volume of oxygen during electrolysis.

Step 4

What is the measure of uncertainty in the 4 experiments?

98%

120 rated

Answer

The measure of uncertainty in the 4 experiments is 9 ± 1 cm<sup>3</sup>, as the range of measurements (from 6 cm<sup>3</sup> to 11 cm<sup>3</sup>) gives a mean of 9 cm<sup>3</sup> with a deviation of 1 cm<sup>3</sup>.

Step 5

Calculate the mass of potassium sulfate needed to make 1.0 dm<sup>3</sup> of solution.

97%

117 rated

Answer

Given that 0.86 g of potassium sulfate is dissolved in 25 cm<sup>3</sup>, the concentration can be calculated as follows:

  1. Convert 25 cm<sup>3</sup> to dm<sup>3</sup>:

    25extcm3=0.025extdm325 ext{ cm}^3 = 0.025 ext{ dm}^3

  2. Calculate concentration:

    ext{Concentration} = rac{0.86 ext{ g}}{0.025 ext{ dm}^3} = 34.4 ext{ g/dm}^3

  3. For 1.0 dm<sup>3</sup> of solution:

    extMass=34.4extg/dm3imes1.0extdm3=34.4extg ext{Mass} = 34.4 ext{ g/dm}^3 imes 1.0 ext{ dm}^3 = 34.4 ext{ g}.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;