Photo AI

This question is about hydrogen chloride and hydrochloric acid - AQA - GCSE Chemistry Combined Science - Question 6 - 2022 - Paper 1

Question icon

Question 6

This-question-is-about-hydrogen-chloride-and-hydrochloric-acid-AQA-GCSE Chemistry Combined Science-Question 6-2022-Paper 1.png

This question is about hydrogen chloride and hydrochloric acid. 1. Complete the dot and cross diagram to represent the bonding in hydrogen chloride on Figure 7. Us... show full transcript

Worked Solution & Example Answer:This question is about hydrogen chloride and hydrochloric acid - AQA - GCSE Chemistry Combined Science - Question 6 - 2022 - Paper 1

Step 1

Complete the dot and cross diagram to represent the bonding in hydrogen chloride on Figure 7.

96%

114 rated

Answer

The dot and cross diagram for hydrogen chloride (HCl) should display a shared pair of electrons between the hydrogen atom (H) and the chlorine atom (Cl). The chlorine atom contains six non-bonding electrons shown as dots (●), while the bonded pair is shown as a cross (×) overlapping to indicate the shared electrons. The final diagram should reflect this arrangement.

Step 2

What is meant by the term strong acid?

99%

104 rated

Answer

A strong acid is one that completely ionizes in aqueous solution. This means that when the acid dissolves in water, it releases all its hydrogen ions (H⁺) into the solution, resulting in a high concentration of H⁺ ions and a low pH.

Step 3

Describe how magnesium can be used to distinguish between a strong acid and a weak acid of the same concentration.

96%

101 rated

Answer

When magnesium is added to a strong acid, it reacts vigorously and fizzes, producing hydrogen gas quickly. In contrast, when added to a weak acid of the same concentration, the reaction occurs at a much slower rate and may produce less fizzing, indicating a weaker acid.

Step 4

What is the change in pH?

98%

120 rated

Answer

The change in pH can be calculated by the formula: extpH=extlog10[extH+] ext{pH} = - ext{log}_{10}[ ext{H}^+]. When the concentration of hydrochloric acid is increased by a factor of 100, the resulting concentration of H⁺ ions also increases by 100 times. Hence, the change in pH is a decrease of 2 units, as each tenfold increase corresponds to a decrease of 1 in pH.

Step 5

Calculate the bond energy X.

97%

117 rated

Answer

To calculate the bond energy X, we can apply the following steps:

  1. Calculate the total bond energy of the bonds broken:

    • Bonds broken: 4×413+C=C+431=2083+C=C4 \times 413 + C=C + 431 = 2083 + C=C
  2. Calculate the total bond energy of the bonds formed:

    • Bonds formed: 346+339+5×413=2750346 + 339 + 5 \times 413 = 2750
  3. The energy released in the reaction is given by energy released=bonds brokenbonds formed\text{energy released} = \text{bonds broken} - \text{bonds formed} Thus, 56=2750208356 = 2750 - 2083 which leads to C=C=611 kJ/molC=C = 611 \text{ kJ/mol}. Therefore, bond energy X is 611 kJ/mol.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;