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A student investigated the temperature change when magnesium was added to copper sulfate solution - AQA - GCSE Chemistry Combined Science - Question 5 - 2020 - Paper 1

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A student investigated the temperature change when magnesium was added to copper sulfate solution. This is the method used. 1. Pour 30 cm³ of copper sulfate soluti... show full transcript

Worked Solution & Example Answer:A student investigated the temperature change when magnesium was added to copper sulfate solution - AQA - GCSE Chemistry Combined Science - Question 5 - 2020 - Paper 1

Step 1

What is the dependent variable in this investigation?

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Answer

The dependent variable in this investigation is the temperature change of the mixture.

Step 2

Suggest why the copper sulfate solution was left for four minutes before adding the magnesium.

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Answer

The copper sulfate solution was left for four minutes to allow it to reach a constant temperature before magnesium was added.

Step 3

Complete Figure 4 by: - drawing a line of best fit through all the points after 7 minutes. - extending the line back to 4 minutes.

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Answer

The line of best fit should show a downward trend through the points after 7 minutes and be extended to connect to the data at 4 minutes.

Step 4

Determine the temperature change for the reaction.

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Answer

At 4 minutes, the temperature was approximately 26.3 °C and at the maximum recorded value shortly after that it was about 17.5 °C. The temperature change is thus calculated as follows:

extTemperaturechange=26.3ext°C17.5ext°C=8.8ext°C ext{Temperature change} = 26.3 ext{ °C} - 17.5 ext{ °C} = 8.8 ext{ °C}

Step 5

Explain why the temperature of the mixture decreases after 7 minutes.

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Answer

The temperature of the mixture decreases after 7 minutes because the reaction has finished or stopped, leading to energy loss to the surroundings or atmosphere; hence, the solution cools back to room temperature.

Step 6

Suggest the identity of metal Q. Give one reason for your answer.

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Answer

Metal Q could be aluminum, zinc, iron, or beryllium because these metals are less reactive than magnesium, resulting in a smaller temperature change.

Step 7

Calculate the mass of copper sulfate in 30.0 cm³ of this solution.

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Answer

To find the mass of copper sulfate in 30.0 cm³ of the solution, we first convert the volume into dm³:

30.0extcm3=0.030extdm330.0 ext{ cm}^3 = 0.030 ext{ dm}^3

Next, using the molarity:

  • Moles = 0.100 moles in 0.500 dm³, hence in 0.030 dm³:
ext{Moles} = 0.030 imes rac{0.1}{0.5} = 0.006 ext{ moles}

Finally, the mass is:

extMass=0.006extmolesimes159.5extg/mol=0.957extg ext{Mass} = 0.006 ext{ moles} imes 159.5 ext{ g/mol} = 0.957 ext{ g}

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