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This question is about hydrogen chloride and hydrochloric acid - AQA - GCSE Chemistry Combined Science - Question 6 - 2022 - Paper 1

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This question is about hydrogen chloride and hydrochloric acid. 1. Complete the dot and cross diagram to represent the bonding in hydrogen chloride on Figure 7. Us... show full transcript

Worked Solution & Example Answer:This question is about hydrogen chloride and hydrochloric acid - AQA - GCSE Chemistry Combined Science - Question 6 - 2022 - Paper 1

Step 1

Complete the dot and cross diagram to represent the bonding in hydrogen chloride on Figure 7.

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Answer

The dot and cross diagram for hydrogen chloride (HCl) shows a single bond formed by one shared pair of electrons between the hydrogen (H) and chlorine (Cl) atoms. The diagram should depict H with one electron (dot) and Cl with one shared electron (cross) along with six non-bonding electrons, represented as crosses, to indicate chlorine's outer shell.

Step 2

What is meant by the term strong acid?

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Answer

A strong acid is one that completely ionizes or dissociates in aqueous solution, resulting in a high concentration of hydronium ions (H₃O⁺) in the solution. This allows strong acids to effectively lower the pH of the solution.

Step 3

Describe how magnesium can be used to distinguish between a strong acid and a weak acid of the same concentration.

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Magnesium can be used to distinguish between strong and weak acids by observing its reactivity. Magnesium reacts more vigorously with strong acids, resulting in rapid fizzing and the quicker disappearance of the magnesium metal. In contrast, the reaction with a weak acid will be slower and less vigorous.

Step 4

What is the change in pH?

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Answer

When the concentration of hydrochloric acid is increased by a factor of 100, the pH decreases by 2. This is calculated using the formula:

extChangeinpH=extlog10(extfactor) ext{Change in pH} = - ext{log}_{10}( ext{factor})

For a factor of 100, the change in pH is:

extChangeinpH=extlog10(100)=2 ext{Change in pH} = - ext{log}_{10}(100) = -2.

Step 5

Calculate the bond energy X.

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Answer

To calculate bond energy X, we need to apply the given bond energies to determine the energy involved in the reaction:

  1. Calculate the total energy of bonds broken:

    • Bonds broken: (4 x 413 kJ/mol) + (C=C bond) = 1652 + x
  2. Calculate the total energy of bonds formed:

    • Bonds formed: (5 x 413) + (C-C) + (C-Cl) = 2065 + 346 + 339 = 2750 kJ/mol
  3. The energy released is 56 kJ/mol greater than the energy required to break the existing bonds:

    • Energy released = Energy broken - Energy formed
    • (1652 + x) - 2750 = -56
    • Solving the above gives: x=611extkJ/molx = 611 ext{ kJ/mol}.

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