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This question is about acids - AQA - GCSE Chemistry - Question 9 - 2021 - Paper 1

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This question is about acids. Hydrogen chloride and ethanoic acid both dissolve in water. All hydrogen chloride molecules ionise in water. Approximately 1% of ethan... show full transcript

Worked Solution & Example Answer:This question is about acids - AQA - GCSE Chemistry - Question 9 - 2021 - Paper 1

Step 1

Which is the correct description of this solution?

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Answer

The solution is described as a dilute solution of a strong acid because hydrogen chloride ionizes completely in water, making it a strong acid.

Step 2

Which solution would have the lowest pH?

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Answer

The solution with 1.0 mol/dm³ hydrogen chloride solution would have the lowest pH since it has the highest concentration of H⁺ ions.

Step 3

Suggest two improvements to the method that would increase the accuracy of the result.

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Answer

  1. Swirl the solution during titration to ensure proper mixing of the reactants.
  2. Use a white tile under the flask during titration to better observe the endpoint color change.

Step 4

Calculate the mass of ethanoic acid (H₂C₂O₄) needed to make 250 cm³ of a solution with concentration 0.0480 mol/dm³.

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Answer

To find the mass, first calculate the number of moles needed:

ext{Moles} = ext{Concentration} imes ext{Volume} = 0.0480 imes rac{250}{1000} = 0.0120 ext{ mol}

Next, calculate the mass using the molar mass:

extMass=extMolesimesextMolarMass=0.0120imes90=1.08extg ext{Mass} = ext{Moles} imes ext{Molar Mass} = 0.0120 imes 90 = 1.08 ext{ g}

Step 5

Calculate the concentration of the sodium hydroxide solution in mol/dm³.

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Answer

Using the reaction stoichiometry, we can determine the moles of H₂C₂O₄ first:

ext{Moles of H₂C₂O₄} = 0.0480 imes rac{15.00}{1000} = 0.00072 ext{ mol}

Since 1 mole of H₂C₂O₄ neutralizes 2 moles of NaOH,

extMolesofNaOH=2imes0.00072=0.00144extmol ext{Moles of NaOH} = 2 imes 0.00072 = 0.00144 ext{ mol}

Now, calculate the concentration:

ext{Concentration} = rac{ ext{Moles}}{ ext{Volume}} = rac{0.00144}{0.0250} = 0.0576 ext{ mol/dm³}

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