Photo AI

This question is about compounds - AQA - GCSE Chemistry - Question 5 - 2015 - Paper 2

Question icon

Question 5

This-question-is-about-compounds-AQA-GCSE Chemistry-Question 5-2015-Paper 2.png

This question is about compounds. Table 2 gives information about the solubility of some compounds. Table 2 Soluble compounds All potassium and sodium salts All ... show full transcript

Worked Solution & Example Answer:This question is about compounds - AQA - GCSE Chemistry - Question 5 - 2015 - Paper 2

Step 1

Name a soluble compound that contains silver ions.

96%

114 rated

Answer

A soluble compound that contains silver ions is silver nitrate, which can be represented chemically as AgNO₃.

Step 2

Name a soluble compound that contains carbonate ions.

99%

104 rated

Answer

A soluble compound that contains carbonate ions is potassium carbonate, represented as K₂CO₃, or sodium carbonate, Na₂CO₃.

Step 3

What type of compound is a metal oxide?

96%

101 rated

Answer

A metal oxide is classified as a base, which is capable of reacting with acids to form salts.

Step 4

State how solid lead nitrate can be obtained from lead nitrate solution.

98%

120 rated

Answer

Solid lead nitrate can be obtained from lead nitrate solution by evaporating the water, which allows the solid to crystallize out as the solution cools.

Step 5

Balance the equation for the reaction.

97%

117 rated

Answer

The balanced equation for the reaction is:

ightarrow ext{Pb(NO}_3)_2 + ext{H}_2 ext{O}$$

Step 6

Give the total number of atoms in the formula Pb(NO3)2.

97%

121 rated

Answer

In the formula Pb(NO₃)₂, there are a total of 9 atoms: 1 lead (Pb), 2 nitrogen (N), and 6 oxygen (O) atoms.

Step 7

Calculate the empirical formula of this lead oxide.

96%

114 rated

Answer

To find the empirical formula, first determine the moles of each element:

  1. Moles of lead: rac{6.21 ext{ g}}{207 ext{ g/mol}} = 0.03
  2. Moles of oxygen: rac{0.72 ext{ g}}{16 ext{ g/mol}} = 0.045

Next, divide both by the smallest number of moles:

  1. For lead: rac{0.03}{0.03} = 1
  2. For oxygen: rac{0.045}{0.03} = 1.5

To obtain whole numbers, multiply by 2: Lead: 2 Oxygen: 3

Thus, the empirical formula is extPb2extO3 ext{Pb}_2 ext{O}_3.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;