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This question is about lithium carbonate - AQA - GCSE Chemistry - Question 2 - 2019 - Paper 2

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This question is about lithium carbonate. Lithium carbonate is used in medicines. Figure 2 shows a tablet containing lithium carbonate. 1. Lithium carbonate conta... show full transcript

Worked Solution & Example Answer:This question is about lithium carbonate - AQA - GCSE Chemistry - Question 2 - 2019 - Paper 2

Step 1

Plan an investigation to show the presence of lithium ions and of carbonate ions in the tablet.

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Answer

To investigate the presence of lithium ions and carbonate ions in the tablet, follow these steps:

  1. Prepare the Tablet Sample:

    • Begin by crushing the tablet into a fine powder or dissolve it in a small amount of water or dilute hydrochloric acid to ensure the complete release of ions.
  2. Test for Lithium Ions:

    • Clean a metal wire and place it over a Bunsen burner until it is red-hot.
    • Dip the wire into the powdered tablet or the solution obtained in step 1.
    • Place the wire back into the flame and observe the color produced. A crimson flame would indicate the presence of lithium ions.
  3. Test for Carbonate Ions:

    • Take a separate sample of the crushed tablet and add dilute hydrochloric acid to it. Look for effervescence (bubbles) which indicates a chemical reaction.
    • Next, bubble the gas produced through limewater (a clear calcium hydroxide solution). If the limewater turns cloudy, it confirms the presence of carbonate ions, as carbon dioxide is a product of the reaction.

Step 2

What name is given to mixtures like tablets?

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Answer

The name given to mixtures like tablets is formulations. Formulations contain various substances carefully combined in fixed amounts for specific therapeutic effects.

Step 3

Calculate the percentage by mass of lithium carbonate in this tablet.

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Answer

To find the percentage by mass of lithium carbonate in the tablet, use the formula:

extPercentage=(mass of lithium carbonatetotal mass of tablet)×100 ext{Percentage} = \left( \frac{\text{mass of lithium carbonate}}{\text{total mass of tablet}} \right) \times 100

Given:

  • Mass of the tablet = 1.20 g = 1200 mg
  • Mass of lithium carbonate = 700 mg

So,

extPercentage=(700mg1200mg)×100=58.33%. ext{Percentage} = \left( \frac{700 \, \text{mg}}{1200 \, \text{mg}} \right) \times 100 = 58.33\%.

Thus, the percentage by mass of lithium carbonate in the tablet is approximately 58.3% (to two significant figures).

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