This question is about the reaction between sodium thiosulfate solution and hydrochloric acid - AQA - GCSE Chemistry - Question 8 - 2022 - Paper 2
Question 8
This question is about the reaction between sodium thiosulfate solution and hydrochloric acid.
When hydrochloric acid is added to sodium thiosulfate solution, the ... show full transcript
Worked Solution & Example Answer:This question is about the reaction between sodium thiosulfate solution and hydrochloric acid - AQA - GCSE Chemistry - Question 8 - 2022 - Paper 2
Step 1
Why does the mixture become cloudy?
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Answer
The mixture becomes cloudy due to the formation of sulfur as a precipitate. Sulfur is produced in the reaction between sodium thiosulfate and hydrochloric acid, which causes the solution to become less transparent.
Step 2
Determine the rate of reaction in moles for the production of sulfur at 30 seconds.
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Answer
To determine the rate of reaction at 30 seconds:
Draw a tangent to the curve at 30 seconds on Figure 7.
Identify the coordinates of the tangent at this point; let’s assume they are reasonable approximations, such as x (30 seconds) and y (percentage of light reached).
Use the formula:
Rate=timechange in mass of sulfur
Calculate the ratio based on the coordinates taken from the tangent. For example, if Δy/Δx=4 (representative of a small square value), then use this to convert and find the moles produced over the specific time, factoring in the scale of the reaction.
Step 3
Explain why the rate of reaction changes between 0 and 60 seconds.
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The rate of reaction decreases between 0 and 60 seconds due to the concentration of reactants decreasing. As the reaction progresses, the concentrations of sodium thiosulfate and hydrochloric acid reduce as they are consumed, leading to fewer particles available to collide and react effectively.
Step 4
Why did the reaction stop?
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The reaction stopped because one of the reactants was completely consumed. When all the sodium thiosulfate or hydrochloric acid has reacted, there are no more reactants left to continue the reaction.
Step 5
Select a line from Figure 6 to show the result you would predict for 0.20 mol/dm³ sodium thiosulfate solution.
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The expected line would depict a steeper decrease in the percentage of light reaching the light sensor compared to the 0.10 mol/dm³ sodium thiosulfate solution, indicating a faster rate of reaction due to the higher concentration.
Step 6
How could the student improve the method so that the same percentages of light reached the light sensor?
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The student could improve the method by stopping light from other sources reaching the light sensor. This minimizes any external light interference that could affect the accuracy of the readings.
Step 7
What was the same in this experiment if similar results were obtained on different days?
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The results were repeatable, indicating that the same method under similar conditions produces consistent and reliable outcomes.
Step 8
Which expression represents the stoichiometry between the volume of sodium thiosulfate solution used and the mass of sulfur produced?
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The correct expression that represents the stoichiometry is V∝m, meaning that the volume of sodium thiosulfate solution is directly proportional to the mass of sulfur produced.
Step 9
Determine the simplest whole number ratio of the volumes of sodium thiosulfate solution : hydrochloric acid.
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The simplest whole number ratio of the volumes can be determined from the reaction equation. Based on the stoichiometric coefficients, the ratio is 1 : 4, indicating that for every 1 volume of sodium thiosulfate, 4 volumes of hydrochloric acid are required.