Photo AI

This question is about silicon and compounds of silicon - AQA - GCSE Chemistry - Question 7 - 2022 - Paper 1

Question icon

Question 7

This-question-is-about-silicon-and-compounds-of-silicon-AQA-GCSE Chemistry-Question 7-2022-Paper 1.png

This question is about silicon and compounds of silicon. The reactivity series sometimes includes non-metals such as carbon, hydrogen and silicon. Silicon can be e... show full transcript

Worked Solution & Example Answer:This question is about silicon and compounds of silicon - AQA - GCSE Chemistry - Question 7 - 2022 - Paper 1

Step 1

Explain what this reaction shows about the position of silicon in the reactivity series.

96%

114 rated

Answer

The reaction indicates that silicon is less reactive than carbon. This is evident because carbon can displace silicon from silicon dioxide, suggesting that silicon is situated lower in the reactivity series compared to carbon.

Step 2

Explain why aluminium is more expensive than carbon.

99%

104 rated

Answer

Aluminium is more expensive than carbon primarily because more energy is required to extract aluminium from its ores through electrolysis, whereas carbon is obtained more cheaply through heating coal.

Step 3

Give one reason why the products are difficult to separate if magnesium is used to reduce silicon dioxide.

96%

101 rated

Answer

Both products, silicon and magnesium oxide, are solid, which makes them difficult to separate by conventional methods.

Step 4

Calculate the minimum mass in grams of magnesium needed to completely reduce 1.2 kg of silicon dioxide.

98%

120 rated

Answer

First, we calculate the molar mass of silicon dioxide (SiO2_2): Mr(SiO2)=28+2×16=60 g/molM_r(SiO_2) = 28 + 2 \times 16 = 60 \ g/mol

Next, we find the moles of SiO2_2 in 1.2 kg: 1200 g60 g/mol=20 moles of SiO2\frac{1200 \ g}{60 \ g/mol} = 20 \ moles \ of \ SiO_2

According to the reaction: 2Mg+SiO2Si+2MgO2Mg + SiO_2 \rightarrow Si + 2MgO

2 moles of magnesium are required for every mole of silicon dioxide, thus: 20 moles of SiO2×2=40 moles of Mg20 \ moles \ of \ SiO_2 \times 2 = 40 \ moles \ of \ Mg

Calculating the mass of magnesium needed: Mr(Mg)=24 g/molM_r(Mg) = 24 \ g/mol 40 moles of Mg×24 g/mol=960 g40 \ moles \ of \ Mg \times 24 \ g/mol = 960 \ g

Step 5

Complete Figure 9 to show the outer shell electrons in a molecule of SiH$_4$.

97%

117 rated

Answer

In SiH4_4, silicon shares its four outer shell electrons with four hydrogen atoms. Each hydrogen atom contributes one electron, resulting in four shared pairs that create a stable octet for silicon.

Step 6

Calculate the total volume of gases present after the reaction.

97%

121 rated

Answer

For 30 cm3^3 of SiH4_4:

determine the volume of oxygen needed: 30 cm3 SiH4×7 (from the equation)=105 cm3 O230 \ cm^3 \ SiH_4 \times 7 \text{ (from the equation)} = 105 \ cm^3 \ O_2

Since we have 150 cm3^3 of O2O_2, the reaction leaves a surplus of: 150 cm3105 cm3=45 cm3 (excess)150 \ cm^3 - 105 \ cm^3 = 45 \ cm^3 \ (excess)

Water vapour formed: 3×30 cm3=90 cm33 \times 30 \ cm^3 = 90 \ cm^3

Total volume of gases present: 45 cm3(excess O2)+90 cm3(H2O)=135 cm345 \ cm^3 (excess \ O_2) + 90 \ cm^3 (H_2O) = 135 \ cm^3

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;