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Question 15
A program has been written in Python to display all the odd integers between 1 and the largest odd number smaller than an integer entered by the user. The program is... show full transcript
Step 1
Answer
To modify the program to allow for any odd integer, we can adjust the while loop's condition. The condition should check if the current odd number is less than the number entered by the user and also ensure it is odd. Here is the modified code:
odd = 1
number = int(input("Enter an integer: "))
while odd < number:
print(odd)
odd += 2
print("Finished!")
In this configuration, the program will print all odd integers from 1 up to the largest odd integer smaller than the user’s input.
Step 2
Answer
To handle the situation where the user enters an odd integer less than 1, we should check if the user input is less than 1. If it is, we can set 'odd' to the largest odd number less than the entered number. Here's how to adjust the code:
odd = 1
number = int(input("Enter an integer: "))
if number < 1:
odd = number if number % 2 != 0 else number - 1
while odd > 0:
print(odd)
odd -= 2
print("Finished!")
In this approach, the program will correctly display odd integers even when the input is less than 1, handling scenarios for any odd integer.
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