Photo AI

A student investigated how the mass of water in an electric kettle affected the time taken for the water to reach boiling point - AQA - GCSE Physics Combined Science - Question 5 - 2019 - Paper 1

Question icon

Question 5

A-student-investigated-how-the-mass-of-water-in-an-electric-kettle-affected-the-time-taken-for-the-water-to-reach-boiling-point-AQA-GCSE Physics Combined Science-Question 5-2019-Paper 1.png

A student investigated how the mass of water in an electric kettle affected the time taken for the water to reach boiling point. The kettle switched off when the wa... show full transcript

Worked Solution & Example Answer:A student investigated how the mass of water in an electric kettle affected the time taken for the water to reach boiling point - AQA - GCSE Physics Combined Science - Question 5 - 2019 - Paper 1

Step 1

Explain why the temperature of the heating element increased.

96%

114 rated

Answer

The temperature of the heating element increased because electrons collide with particles in the heating element. This collision transfers energy to the particles, increasing their kinetic energy and leading to a rise in temperature.

Step 2

Give one variable that the student should have controlled.

99%

104 rated

Answer

The starting temperature of the water should have been controlled to ensure consistency in the experiment.

Step 3

Suggest why the line on Figure 5 does not go through the origin.

96%

101 rated

Answer

The line does not go through the origin because there is a minimum mass of water needed for boiling; thus, even with zero water mass, there is a non-zero time for the kettle to switch off.

Step 4

Suggest why the results give a non-linear pattern.

98%

120 rated

Answer

The results give a non-linear pattern because as the mass of water increases, the energy required to heat the water increases disproportionately due to factors such as increased heat loss to the surroundings.

Step 5

Calculate the specific heat capacity of water using this information.

97%

117 rated

Answer

First, we calculate the total energy transferred using the formula:

E=Pimest=2600extWimes120exts=312000extJE = P imes t = 2600 ext{ W} imes 120 ext{ s} = 312000 ext{ J}

Then, using the equation for specific heat capacity:

E=mchetaE = mc heta

we rearrange to find the specific heat capacity, cc:

c=EmΔθ=312000extJ0.80extkg×(10018)=3120000.80×82=4800extJ/kg°Cc = \frac{E}{m\Delta \theta} = \frac{312000 ext{ J}}{0.80 ext{ kg} \times (100 - 18)} = \frac{312000}{0.80 \times 82} = 4800 ext{ J/kg °C}

Therefore, the specific heat capacity of water is approximately 4800 J/kg °C.

Join the GCSE students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;