Figure 4 shows a child playing with a toy train - AQA - GCSE Physics Combined Science - Question 3 - 2022 - Paper 2
Question 3
Figure 4 shows a child playing with a toy train.
The train is on a bridge.
When the child lets go of the train, the train rolls down the bridge.
The momentum of t... show full transcript
Worked Solution & Example Answer:Figure 4 shows a child playing with a toy train - AQA - GCSE Physics Combined Science - Question 3 - 2022 - Paper 2
Step 1
Calculate the velocity of the train at the bottom of the bridge.
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Answer
To find the velocity of the train, we use the formula for momentum:
p=mv
Where:
p is the momentum (0.216 kg·m/s)
m is the mass in kg (180 g = 0.180 kg)
v is the velocity in m/s.
Substitute the known values into the formula:
0.216=0.180⋅v
Rearranging gives:
v=0.1800.216
Calculating this yields:
v=1.2 m/s
Thus, the velocity of the train at the bottom of the bridge is 1.2 m/s.
Step 2
Explain why the velocity of the train after the collision is less than it was before the collision.
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Answer
The total momentum is conserved in a collision. This means that the momentum of the train before the collision is equal to the momentum of the train plus the stationary carriage after the collision:
During the collision, the momentum of the carriage increases because it starts moving and gains momentum.
Consequently, the momentum of the train decreases as it transfers some of its momentum to the stationary carriage.
Since momentum is defined as:
momentum=mass×velocity,
it follows that if the mass of the train remains constant but some of its velocity is transferred to the carriage, the velocity of the train must decrease.