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Figure 4 shows a child playing with a toy train - AQA - GCSE Physics Combined Science - Question 3 - 2022 - Paper 2

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Figure 4 shows a child playing with a toy train. The train is on a bridge. When the child lets go of the train, the train rolls down the bridge. The momentum of t... show full transcript

Worked Solution & Example Answer:Figure 4 shows a child playing with a toy train - AQA - GCSE Physics Combined Science - Question 3 - 2022 - Paper 2

Step 1

Calculate the velocity of the train at the bottom of the bridge.

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Answer

To find the velocity of the train, we use the formula for momentum: p=mvp = mv Where:

  • pp is the momentum (0.216 kg·m/s)
  • mm is the mass in kg (180 g = 0.180 kg)
  • vv is the velocity in m/s.
  1. Substitute the known values into the formula: 0.216=0.180v0.216 = 0.180 \cdot v
  2. Rearranging gives: v=0.2160.180v = \frac{0.216}{0.180}
  3. Calculating this yields: v=1.2 m/sv = 1.2 \text{ m/s}

Thus, the velocity of the train at the bottom of the bridge is 1.2 m/s.

Step 2

Explain why the velocity of the train after the collision is less than it was before the collision.

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Answer

The total momentum is conserved in a collision. This means that the momentum of the train before the collision is equal to the momentum of the train plus the stationary carriage after the collision:

  • During the collision, the momentum of the carriage increases because it starts moving and gains momentum.
  • Consequently, the momentum of the train decreases as it transfers some of its momentum to the stationary carriage.

Since momentum is defined as: momentum=mass×velocity,\text{momentum} = \text{mass} \times \text{velocity}, it follows that if the mass of the train remains constant but some of its velocity is transferred to the carriage, the velocity of the train must decrease.

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