Complete the sentences - AQA - GCSE Physics - Question 7 - 2021 - Paper 1

kinetic energy.

The equation is given by:

$E_k = 0.5 \times m \times v^2$

or

$E_k = \frac{1}{2}mv^2$

Given the kinetic energy is 5040 J and the speed is 12 m/s, we use the equation:

$5040 = 0.5 \times m \times (12)^2$

Now calculate:

1. First calculate $(12)^2 = 144$

2. Substitute back into the equation:

$5040 = 0.5 \times m \times 144$

3. Rearranging gives:

$m = \frac{5040}{0.5 \times 144}$

4. Calculate:

$m = \frac{5040}{72} = 70 \text{ kg}$

The thermal energy increases.