A student investigated how the current in a filament lamp varied with the potential difference across the filament lamp - AQA - GCSE Physics - Question 1 - 2020 - Paper 1
Question 1
A student investigated how the current in a filament lamp varied with the potential difference across the filament lamp.
Figure 1 shows part of the circuit used.
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Worked Solution & Example Answer:A student investigated how the current in a filament lamp varied with the potential difference across the filament lamp - AQA - GCSE Physics - Question 1 - 2020 - Paper 1
Step 1
Complete Figure 1 by adding an ammeter and a voltmeter.
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Answer
To complete Figure 1, add an ammeter in series with the filament lamp, and a voltmeter in parallel with the filament lamp. Use the correct circuit symbols:
Ammeter: A circle with 'A' inside it and a straight line representing the wire.
Voltmeter: A circle with 'V' inside it and two lines connecting across the filament lamp.
Step 2
Draw a line on Figure 2 to show the relationship between the negative values of current and potential difference.
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Answer
To show the relationship in Figure 2, draw a smooth, curved line that connects the negative values of potential difference and current. The line should reflect the trend, passing through points like (-4.0 V, -0.2 A) and (-6.0 V, -0.23 A). Ensure that the line does not become horizontal.
Step 3
Write down the equation which links current (I), potential difference (V) and resistance (R).
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Answer
The equation that links current (I), potential difference (V) and resistance (R) is given by:
V=I×R
Step 4
Determine the resistance of the filament lamp when the potential difference across it is 1.0 V.
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Answer
From Figure 2, when the potential difference, V = 1.0 V, the current, I = 0.08 A.